(I have two questions)
2 answers:
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Answer:
The given sequence 6, 7, 13, 20, ... is a recursive sequence
Step-by-step explanation:
As the given sequence is
- It cannot be an arithmetic sequence as the common difference between two consecutive terms in not constant.
As
,
As d is not same. Hence, it cannot be an arithmetic sequence.
- It also cannot be a geometrical sequence and exponential sequence.
It cannot be geometric sequence as the common ratio between two consecutive terms in not constant.
As
,
,
As r is not same, Hence, it cannot be a geometric sequence or exponential sequence. As exponential sequence and geometric sequence are basically the same thing.
So, if we carefully observe, we can determine that:
- The given sequence 6, 7, 13, 20, ... is a recursive sequence.
Please have a close look that each term is being created by adding the preceding two terms.
For example, the sequence is generated by starting from 1.
and
for n > 1.
<em>Keywords: sequence, arithmetic sequence, geometric sequence, exponential sequence</em>
<em>Learn more about sequence from brainly.com/question/10986621</em>
<em>#learnwithBrainly</em>
Hi there!
I can see why you've posted a question like this here - For adding, subtracting, multiplying, or dividing fractions by whole numbers can be difficult to come out with a precise answer, so let me make it look easier for you!
So, the steps are:
Smush the 2 (whole number) and the 2 (the numerator of the fraction) together on top so its (2)(2) over 6. I can show you what I mean, if you'd like.
This is what it should look like.
Now, what is 2 times 2? You can use a calculator for this part.
Now, we can get to the last part, my favorite one!
Simplify down to
.
How did we do it? EASY!
See what number does evenly into both numerators and denominators. In this case, 2 goes into 4 twice, and 2 goes into 6 three times, so we're left with our beautiful answer .
That wasn't so bad, was it? You can use this as a guide for figuring out math problems like these, in case you're stuck again. But just in case, message me if you need anymore help! :D