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3 years ago

In a sequence of numbers, a3=3, a4=7, a5=11, a6=15 a7=19.

Mathematics

1 answer:

zalisa [80]3 years ago

3 0

Answer:

B, an = 4n - 9

Step-by-step explanation:

The sequence is for every time the exponent on a goes up one, the number that it equals to goes up by 4. So to find the nth term, we at 4 to n. I hope this helped! :)

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How would you set this problem up to find x?

Elina [12.6K]

Answer:

33x - 13 = 13x + 7

Step-by-step explanation:

If "G" is the midpoint of line FH, then both segments (lines FG and GH) must be the same length. Therefore, to find "x", you can set both segments equal to each other. After doing this, you can simplify and isolate to find "x".

FG = 33x - 13

GH = 13x + 7

FG = GH

33x - 13 = 13x + 7

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2 years ago

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Can someone please help me ASAP

riadik2000 [5.3K]

Answer:

(-4,0) (0,3)

(3-0)/(0+4)= 3/4

y - 0 = 3/4(x + 4)

y = 3/4x + 3

answer is a

Step-by-step explanation:

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4 years ago

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What is 4% of 720? i need help for a test

boyakko [2]

Answer:

28.8

Step-by-step explanation:

4% x 720

0.04 x 720

= 28.8

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3 years ago

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Triangle JKL is shown on the grid below. Triangle J'K'L' is the image of triangle JKL under a 90 degree clockwise rotation about

zheka24 [161]

Answer:

J (-4 , 1) -> J' (1 , 4)

K (-2 , 1) -> K' (1 , 2)

L (-2 , 5) -> L' (5 , 2)

Step-by-step explanation:

clockwise rotation 90°: (x,y) -> (y,-x)

J (-4 , 1) -> J' (1 , 4)

K (-2 , 1) -> K' (1 , 2)

L (-2 , 5) -> L' (5 , 2)

3 0

3 years ago

Researchers suspect that 18% of all high school students smoke at least one pack of cigarettes a day. At the local high school,

Nataliya [291]

Answer:

We conclude that 18% of all high school students smoke at least one pack of cigarettes a day.

Step-by-step explanation:

We are given that researchers suspect that 18% of all high school students smoke at least one pack of cigarettes a day.

At the local high school, a randomly selected sample of 300 students found that 50 students smoked at least one pack of cigarettes a day.

Let p = proportion of all high school students who smoke at least one pack of cigarettes a day.

So, Null Hypothesis, $H_0$ : p = 18% {means that 18% of all high school students smoke at least one pack of cigarettes a day}

Alternate Hypothesis, $H_A$ : p < 18% {means that less than 18% of all high school students smoke at least one pack of cigarettes a day}

The test statistics that would be used here is One-sample z -test for proportions because we are given with the proportions values;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students who smoked at least one pack of cigarettes a day = $\frac{50}{300}$ = 0.167

n = sample of students = 300

So, test statistics = $\frac{0.167-0.18}{\sqrt{\frac{0.167(1-0.167)}{300} } }$

= -0.604

The value of z test statistics is -0.604.

Also, P-value of the test statistics is given to us is 0.2743.

Since, the P-value of test statistics is more than the level of significance as 0.2743 > 0.025, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that 18% of all high school students smoke at least one pack of cigarettes a day.

6 0

3 years ago