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Paha777 [63]
3 years ago
7

Help please dghsshjhjs

Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0

Answer:

D

Step-by-step explanation:

There is more than one way to solve this; the easiest way is to plug in some numbers for x. We can see the roots are (3,0) and (7,0) and the lowest point is (5,0). So when we plug in 3 or 7, we should get zero.

B: (3-3)(3-7)=0

D: 3(3-3)(3-7)=0

So we have two possible solutions, So to check, let's find a point where we can easily find the y value.

When x is equal to 4,5, or 6, there is an integer value for y. so let's plugin 5:

(5-3)(5-7)=-4

We can see when x is five, y has to be -12, so that is not the answer, thus d is the final answer.

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Given: A, B, and C What is the value of X in the matrix equation AX + B = C?
Ksju [112]

Answer:

Option (2)

Step-by-step explanation:

Given expression is, AX + B = C

A=\begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}

B=\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix}

C=\begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}

AX + B = C

AX = C - B

C - B = \begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}-\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix} = \begin{bmatrix}-42+7 & -20+9\\ 5-4 & 4+1\end{bmatrix}

C - B = \begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Let  X=\begin{bmatrix}a & b\\ c & d\end{bmatrix}

AX = \begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}\times \begin{bmatrix}a & b\\ c & d\end{bmatrix}

     = \begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}

Since AX = C - B

\begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}=\begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Therefore, a = 1, b = 5

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3(1) + 4c = 35

3 + 4c = 35

4c = 32

c = 8

And (-3b - 4d) = -11

3(5) + 4d = 11

4d = -4

d = -1

Therefore, Option (2). X = \begin{bmatrix}1 & 5\\ 8 & -1\end{bmatrix} will be the answer.

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Answer:

Image below

Step-by-step explanation:

<em>Given: Side lengths of a right triangle 3,4 and 5 units. </em>

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