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3 years ago

Use the log table to estimate the value of log10 8.65.

Mathematics

2 answers:

Shalnov [3]3 years ago

8 0

I think it is 86.5, but that's just me.

Afina-wow [57]3 years ago

5 0

Answer:

0.9370

Step-by-step explanation:

The logarithmic table (of base 10) is used like this:

First turn the number in scientific notation, but in this case, the number is small and already in "scientific notation", 8.65.

Take the number 8.65 and divide it, first two numbers first and then all the others, one by one.

Locate 8.6 at the left, then the next number, 5 would be at the top, if you had any other number after the 5 you would look for it in the mean difference part, and then would add the number you get, divided by 1000 to the number you found from 8.6 and 5. The image attached shows a good reference to understand this

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Roberto deposited $5,000 into an account with 4.2% interest, compounded monthly.

Marina86 [1]

Answer:

$50,581.9

Step-by-step explanation:

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3 years ago

2. To estimate the mean age for a population of 4000 employees, a simple random sample of 40 employees is selected. a. Would you

ANEK [815]

Answer:

Step-by-step explanation:

Size of the population, N = 4000

Size of the sample, n = 40

n/N = 40/4000 = 0.01

0.01 is less than 0.05 and hence we would not us the finite population correction factor in calculating the standard error of the mean.

Population standard deviation is σ = 8.2

So, the standard error of x’ using the finite population correction factor is give by

σ(x’) = √[(N - n)/(N - 1)] x (sigma/√n)

σ(x’) = √[(4000 - 40)/(4000 - 1)] x (8.2/√40)

σ(x’) = 1.29

Standard error of x’ without using the finite population correction factor is

σ(x’) = σ/√n

σ(x’) = 8.2/√40 = 1.2965

There is little difference between the two values of the standard error. So we can ignore the population correction factor.

Let the population mean be μ

Probability that the sample mean will be within =-2 of the population mean is

P(μ– 2 < x’ < μ + 2)

At x’ = μ – 2 , we have

z = (μ – 2 – μ)/1.2965

z = -1.54

at x’ = μ + 2, we have

z = (μ + 2 – μ)/1.2965

z = 1.54

So the required probability is

P(μ – 2 < x’ < μ + 2) = p(-1.54< z < 1.54)

P(μ – 2 < x’ < μ + 2) = p(z < 1.54) – p(z < -1.54)

P(μ – 2 < x’ < μ + 2) = 0.9382 – 0.0618

P(μ – 2 < x’ < μ + 2) = 0.8764

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3 years ago

Plis necesito ayuda en esta tarea:

Ede4ka [16]

Answer:

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3 years ago

Solve for the given length. The length of a rectangle is 3m longer than its width. The area of the rectangle is 154^2. What is t

Andre45 [30]

If the length of a rectangle is 3m longer than its width, then:
L=W+3
Is the area really 154^2? Or is it 154m^2? If yes, then:
A=LW
154=(W+3)(W)
154=(W^2+3W)
0=W^2+3W-154
0=(W-11)(W+14)
This means either (W-11) or (W+14) is equal to zero so:
W=11 and W=-14
To find out let's substitute the numbers:
154=(11+3)(11)
154=154
Therefore, the width of the rectangle is 11m

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3 years ago

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