<img src="https://tex.z-dn.net/?f=e%20%3D%20%20%5Cfrac%7Bo%20%2B%204m%20%2B%20p%7D%7B6%7D%20" id="TexFormula1" title="e = \frac

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Ludmilka [50]

2 years ago

{o + 4m + p}{6} " alt="e = \frac{o + 4m + p}{6} " align="absmiddle" class="latex-formula">
find in terms of p

Mathematics

1 answer:

evablogger [386]2 years ago

4 0

$\dfrac{o+4m+p}{6}=e\qquad\text{multiply both sides by 6}\\\\o+4m+p=6e\qquad\text{subtract o and 4m from both sides}\\\\\boxed{p=6e-o-4m}$

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Now suppose instead that Jane withdraws $500 from her checking account and uses $300 of this money to pay her federal income tax

zysi [14]

Answer:

Step-by-step explanation:

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3 years ago

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When 508,000,000 is written in scientific notation, what will be the value of the decimal number? pizzzz help

yuradex [85]

Answer:

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Step-by-step explanation:

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3 years ago

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Maru [420]

Answer:

$9\text{ln}|x|+2\sqrt{x}+x+C$

Step-by-step explanation:

We have been an integral $\int \frac{9+\sqrt{x}+x}{x}dx$ . We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

$\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx$

$\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx$

Now, we will apply the sum rule of integrals as:

$\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx$

$9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx$

Using common integral $\int \frac{1}{x}dx=\text{ln}|x|$ , we will get:

$9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx$

Now, we will use power rule of integrals as:

$9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx$

$9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx$

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We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

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Therefore, our required integral would be $9\text{ln}|x|+2\sqrt{x}+x+C$ .

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2 years ago

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Ymorist [56]

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