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Natasha_Volkova [10]
2 years ago
8

Y’all I need help with this

Mathematics
1 answer:
topjm [15]2 years ago
3 0

Answer:

k = 5

Step-by-step explanation:

Since the quantities are in direct proportion then the equation relating them is

y = kx ← k is the constant of proportion

The y- axis is number of cups and x- axis is pounds of sugar

To find k use any of the 5 points highlighted on the graph

Using (8, 40 ), then

40 = 8k ( divide both sides by 8 )

5 = k

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Point D(-3.5) is a vertex of triangle DEF.After a rotation of the triangle about the origin, D' is located at (3,-5).Which of th
Nimfa-mama [501]
<h3>Answer: 180 degrees</h3>

note: it doesn't matter if its clockwise or counterclockwise when it comes to 180 degree rotations.

========================================

Explanation:

The rule for 180 degree rotations is

(x,y) ---> (-x, -y)

So the x and y coordinates flip in sign from positive to negative, or vice versa.

Point D ' (-3, 5) rotates to D ' (3, -5) following this rule

-----------------

A further detailed break down might look like this

x = -3 becomes -x = -(-3) = 3

y = 5 becomes -y = -5

(-3, 5) ----> (3, -5)

6 0
3 years ago
Can someone give an explaination please<br><br>​
iren [92.7K]

Answer:

x ≥ -3

x ≤ 3

Step-by-step explanation:

For the first inequality, just add 3 to both sides.

For the second inequality, add 4 to both sides then divide both sides by 3.

3 0
3 years ago
Anyone got answers need help
Mkey [24]

∠DCE = ∠BAE because of alternate interior ∠s

∠CDE = ∠ABE because of alternate interior ∠s

Triangle DCE is congruent to Triangle BAE because of ASA

AE = CE because of CPCTC

BE = DE because of CPCTC

4 0
3 years ago
. Use the quadratic formula to solve each quadratic real equation. Round
Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
How many balls can Michael predict to hit if he is pitched 20 balls?
Vinvika [58]
If Michael is pitched 20 balls he will at least hit ten of them!
7 0
3 years ago
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