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2 answers:
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First, solve the inequality:
Since x is <u>greater than</u> -8, you have the arrow point up the graph towards the positive side starting at -8.
Since it's greater than but not equal to -8, the circle is open.
Thus your graph is D.
Since x is <u>greater than</u> -8, you have the arrow point up the graph towards the positive side starting at -8.
Since it's greater than but not equal to -8, the circle is open.
Thus your graph is D.
Answer:
Step-by-step explanation:
Given that:
The differential equation;
The above equation can be better expressed as:
The pattern of the normalized differential equation can be represented as:
y'' + p(x)y' + q(x) y = 0
This implies that:
Also;
From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2
When x = - 2
Hence, one (1) of them is non-analytical at x = 2.
Thus, x = 2 is an irregular singular point.