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posledela
3 years ago
14

What is 9×8 I hope you explain it

Mathematics
2 answers:
n200080 [17]3 years ago
6 0
9 x 8 = 72 

9 + 9 +9 + 9 + 9 +9 + 9 + 9 = 72
Kisachek [45]3 years ago
5 0
9x8 is 72 because you just ad 9 eight times like 9+9+9+9+9+9+9+9 or you could do 8 nine time like 8+8+8+8+8+8+8+8+8
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Simplify the expression: (3 − 4i) + (7 − 6i). 4 − 2i 4 − 10i 13 − 2i 10 − 10i
yulyashka [42]

Equivalent expressions are expressions of equal values

The simplified expression of (3 - 4i) + (7 - 6i) is 10- 10i

The expression is given as:

(3 - 4i) + (7 - 6i)

Remove brackets in the above expression

3 - 4i + 7 - 6i

Rewrite the expression by collecting the like terms

3 + 7- 4i  - 6i

Next, evaluate the like terms

10- 10i

Hence, the simplified expression of (3 - 4i) + (7 - 6i) is 10- 10i

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brainly.com/question/2972832

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3 years ago
1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro
alex41 [277]

Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

P(VISA \:| \:AE) = 15\%\\

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}

For the given problem it becomes

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

8 0
3 years ago
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