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3 years ago

I will give brainliest pls awnser pls awnser

Mathematics

2 answers:

bogdanovich [222]3 years ago

5 0

Answer:

The two cities would be 17.5 inches from one another on the map

Step-by-step explanation:

i got it correct on edge

svlad2 [7]3 years ago

4 0

The two cities would be 17.5 inches from one another on the map

You might be interested in

Robert has 99 buttons. Jack has b more buttons than Robert. Choose the expression that shows how many buttons Jack has

MAVERICK [17]

Solution:

Note that:

Robert + b = Jack
Robert = 99 buttons

Substituting the values into the equation:

Robert + b = Jack
=> 99 + b = Jack

This means that Jack has 99 + b buttons.

5 0

3 years ago

Need help finding the dimension to this

gladu [14]

D. 2,400 sq. ft. is the closest
1) Convert mixed numbers to improper fractions...
6 1/12 = 73/121 and 11 5/6 = 71/6

2) To get area of one tile, multiply length x width...73/121 times 71/6 = 5,183/72 = 72 sq. in. or 6 sq. ft.

3) 6 sq. ft. times 408 tiles = 2,448 sq. ft.

3 0

3 years ago

Yes or No The volume is the number of cubic units needed to fill a solid figure.

Mademuasel [1]

Correct! ————————————————

7 0

3 years ago

Read 2 more answers

-5(1 - r) - 2 Find r

Grace [21]

Answer:

-5+5r-2 -->

--> 5r-7 <--

Explanation --

Distribute from the parentheses, of course excluding the -2 because it isn't involved, and you'll get --> -5 + 5r -2

Simplify by putting the like terms together (subtract) -->

5r -7 (you get -7 by doing -5-2, and you leave 5r by itself since it doesn't have anything more to simplify with or has any other like term)

So, the final, simplified answer -->

5r-7

Hope this helps!! Have a nice day! :)

7 0

3 years ago

Any 10th grader solve it for 50 points

kkurt [141]

Answer:

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0$ is proved for the sum of pth, qth and rth terms of an arithmetic progression are a, b,and c respectively.

Step-by-step explanation:

Given that the sum of pth, qth and rth terms of an arithmetic progression are a, b and c respectively.

First term of given arithmetic progression is A

and common difference is D

ie., $a_{1}=A$ and common difference=D

The nth term can be written as

$a_{n}=A+(n-1)D$

pth term of given arithmetic progression is a

$a_{p}=A+(p-1)D=a$

qth term of given arithmetic progression is b

$a_{q}=A+(q-1)D=b$ and

rth term of given arithmetic progression is c

$a_{r}=A+(r-1)D=c$

We have to prove that

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)=0$

Now to prove LHS=RHS

Now take LHS

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)$

$=\frac{A+(p-1)D}{p}\times (q-r)+\frac{A+(q-1)D}{q}\times (r-p)+\frac{A+(r-1)D}{r}\times (p-q)$

$=\frac{A+pD-D}{p}\times (q-r)+\frac{A+qD-D}{q}\times (r-p)+\frac{A+rD-D}{r}\times (p-q)$

$=\frac{Aq+pqD-Dq-Ar-prD+rD}{p}+\frac{Ar+rqD-Dr-Ap-pqD+pD}{q}+\frac{Ap+prD-Dp-Aq-qrD+qD}{r}$

$=\frac{[Aq+pqD-Dq-Ar-prD+rD]\times qr+[Ar+rqD-Dr-Ap-pqD+pD]\times pr+[Ap+prD-Dp-Aq-qrD+qD]\times pq}{pqr}$

$=\frac{Arq^{2}+pq^{2} rD-Dq^{2} r-Aqr^{2}-pqr^{2} D+qr^{2} D+Apr^{2}+pr^{2} qD-pDr^{2} -Ap^{2}r-p^{2} rqD+p^{2} rD+Ap^{2} q+p^{2} qrD-Dp^{2} q-Aq^{2} p-q^{2} prD+q^{2}pD}{pqr}$