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shepuryov [24]
3 years ago
14

Can someone help me with B?

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
8 0

its kinda hard but when I closed your screen I didn't see any questionsir

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Find the slope and y intercept of the line represented by each table
d1i1m1o1n [39]

5. m=3 because 6/2 is the slope. b= 1

6. m= -4 because -20/5 is the slope. b= 140

5 0
3 years ago
Triangle ABC has vertices A(1,2), B(1,5), and C(4,2) and undergoes a transformation. Circle the set of vertices that does not be
allochka39001 [22]
The statement says, "Triangle ABC has vertices A(1,2), B(1,5), and C(4,2) and undergoes a transformation."

The question asked is to find the set of vertices that does not belong to the group. This means that an attachment is expected to be there. The absence of any attachment makes this question hard to answer. Maybe this helps answer you question.

8 0
3 years ago
What are the roots of the polynomial equation x cubed minus 5 x + 5 = 2 x squared minus 5?
Dennis_Churaev [7]

Roots of the polynomial x^3-5x+5=2x^2-5 are x=\sqrt{5},x=-\sqrt{5}\,\,and\,\,x=2

Step-by-step explanation:

We need to find roots of the polynomial equation: x^3-5x+5=2x^2-5

Solving the polynomial to find roots:

x^3-5x+5=2x^2-5\\Rearranging:\\x^3-5x+5-2x^2+5=0\\x^3-2x^2-5x+10=0

Finding factors by grouping:

(x^3-2x^2)(-5x+10)=0\\Finding\,\,common\,\,terms:\\x^2(x-2)-5(x-2)=0\\(x^2-5)(x-2)=0\\x^2-5=0\,\,and\,\,x-2=0\\x^2=5\,\,and\,\,x=2\\x=\pm \sqrt{5}\,\,and\,\,x=2

So, roots of the polynomial x^3-5x+5=2x^2-5 are x=\sqrt{5},x=-\sqrt{5}\,\,and\,\,x=2

Keywords: Roots of Polynomial

Learn more about Roots of Polynomial at:

  • brainly.com/question/2568692
  • brainly.com/question/1464739
  • brainly.com/question/1332667
  • brainly.com/question/2364381

#learnwithBrainly

8 0
3 years ago
2x+3b = x-b solve for b
steposvetlana [31]

b= -1/4 x

Step-by-step explanation:

2x+3b=x−b

Step 1: Add b to both sides.

3b+2x+b=−b+x+b

4b+2x=x

Step 2: Add -2x to both sides.

4b+2x+−2x=x+−2x

4b=−x

Step 3: Divide both sides by 4.

4b/4 = -x/4

b= -1/4 x

6 0
3 years ago
If x+3/3 = y+2/2 then x/3 =
lukranit [14]
I'd say first isolate the "x"
(x+3)/3=(y+2)/2
x+3=3*(y+2)/2
x=3(y+2)/2 -3

so we get "x" equals three times "y" plus two which is then divided by two and subtracted by three.

after that I would simply divide both sides by three as shown below

x/3=( 3*(y+2)/2  -3)/3

x/3 =(y+2)/2 -1  (answer simplified)

5 0
3 years ago
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