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3 years ago

Can someone help me with B?

Mathematics

1 answer:

Brilliant_brown [7]3 years ago

8 0

its kinda hard but when I closed your screen I didn't see any questionsir

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Suppose that a random sample of 10 adults has a mean score of 62 on a standardized personality test, with a standard deviation o

aniked [119]

Answer:

The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.645*\frac{4}{\sqrt{10}} = 2.08$

The lower end of the interval is the sample mean subtracted by M. So it is 62 - 2.08 = 59.92

The upper end of the interval is the sample mean added to M. So it is 62 + 2.08 = 64.08.

The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.

5 0

2 years ago

Need help please! Not sure how to do this

Kisachek [45]

This problem is fairly simple if you know the exponential equation, you start with y=78(.17)^x. the you put 10=78(.17)^x, then you solve for x

10=78(.17)^x
-78
-68=.17^x
divide .17 then you have your answer!!

3 0

3 years ago

What is the result when the following code is run? double x = 1; double y = 1; int i = 0; do { y = x / 2; x = x + y; i = i + 1;

Mama L [17]

Answer:

The answer is: 3

Step-by-step explanation:

1. At the begining of the program we start by declairing the variables:

double x=1, double y=1 and int i=0.

2. The structure do...while is used to defined the loop. x<2.5 is the finalization condition of the loop. i is the counter of the loop.

y=x/2 is the first calculation

x=x+y is the second one. Here is where the values of the variable x changes.

a) for the first iteration, the values of y and x are shown below:

$\\\\x=1\\y=1\\y=1/2=0.5\\x=1+0.5=1.5\\i=1$

The variable x is minor to 2.5 so the loop will continue computing.

b) the second iteration, the values of y and x are shown below::

$y=0.5\\x=1.5\\y=\frac{1.5}{2}=0.75\\ x=1.5+0.75=2.25\\i=2$

The variable x is still minor to 2.5 so the loop will continue computing.

c) third iteration:

$y=0.75\\x=2.25\\y=\frac{2.25}{2} =1.1125\\x=2.25+1.125=3.375\\i=3$

The condition x<2.5 is not true so the loop ends.

3. System.out.print(i + " "); displays the value of the variable i wich value is 3.

Therefore the number 3 is display.

6 0

3 years ago

Help!!!! please!!!!!

Serggg [28]

Answer:

Step-by-step explanation:

4x2+4x2+5x2+5x2+5x4+5x4

5 0

3 years ago

Read 2 more answers

What is the value of the second quartile (Q2) of the data set?

Alekssandra [29.7K]

45, 51, 52, 58, 61, 63, 66, 72, 74

You're trying to find the second quartile (Q₂), and to find that, you must find the median, and then find the median within the second half of the median :)

Median (Middle Number) : 61

Now, look at 61, and look at 74. What is the median of those numbers in this set?

Q₂ = 66

So, your quartile 2 is 66.

~Hope I helped!~

7 0

3 years ago