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2 years ago

11

The direct distance from a starting point to a finish line is 20 miles. Unfortunately, you can't take the direct route. If you t

ravel 16 miles west, how many miles south must you travel to reach the finish line? A. 12 B. 16 C. 4

1 answer:

ira [324]2 years ago

6 0

Answer:

12

Step-by-step explanation:

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Point P on the number line shows Lara's score after the first round of a quiz: A number line is shown from negative 8 to 0 to po

Luda [366]

Answer:

The correct group of answer is D) 3 + (−4) = −1, because −1 is 4 units to the left of 3

Step-by-step explanation:

Consider the provided information.

Point P on the number line shows Lara's score after the first round of a quiz:

Point P is shown on 3.

That means after the first round her total was 3.

In round two, she lost 4 points.

Therefore, she score −4 points in 2nd round

To find the total points at the end of round 2, we need to add -4 to 3.

3+(−4)=−1

Here −1 is 4 units to the left of 3.

Hence, the correct group of answer is D) 3 + (−4) = −1, because −1 is 4 units to the left of 3

3 0

3 years ago

Read 2 more answers

Create a linear function that has a solution at (-2,6)

xenn [34]

(x,y) so you start at the orgin and go down two because it's negative. then you go right six and plot your point.

negative number - down or left

positive number - up or right

8 0

3 years ago

Read 2 more answers

A water storage tank is in the shape of a cone with the pointed end down. If the radius is 21 feet and the depth of the tank is

andre [41]

The volume of the water storage tank is the amount of space in it

The volume of the water storage tank is 6468 cubic feet

<h3>How to determine the volume?</h3>

The given parameters are:

Radius (r) = 21 feet

Height (h) = 14 feet

The shape of the water storage tank is a cone.

And the volume of a cone is:

V = 1/3πr^2h

So, we have:

V = 1/3 * 22/7 * 21^2 * 14

This gives

V = 6468

Hence, the volume of the water storage tank is 6468 cubic feet

Read more about volumes at:

brainly.com/question/1972490

4 0

2 years ago

At a hardware store, a tool set normally costs $80. During a sale this week, the tool set costs $12 less than usual. What percen

Hoochie [10]

, $15\%$ of the usual price is the savings .

<u>Step-by-step explanation:</u>

Here we have , At a hardware store, a tool set normally costs $80. During a sale this week, the tool set costs $12 less than usual. We need to find What percentage of the usual price is the savings . Let's find out:

Initially we have cost as $80 , in sale it is $12 less i.e.

⇒ $80-12$

⇒ $68$

So , percentage of the usual price is the savings :

⇒ $\frac{80-68}{80}(100)$

⇒ $\frac{12}{80}(100)$

⇒ $\frac{3(4)}{20(4)}(100)$

⇒ $\frac{3}{20}(100)$

⇒ $3(5)$

⇒ $15\%$

Therefore , $15\%$ of the usual price is the savings .

8 0

3 years ago

In order to help identify baby growth patterns that are unusual, we need to construct a confidence interval of the mean head cir

sukhopar [10]

Answer:

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

Step-by-step explanation:

Our sample size is 100.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 100-1 = 99$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-\alpha}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 99 and 0.005 in the t-distribution table, we have $T = 2.626$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{1.6}{\sqrt{100}} = 0.16$

Now, we multiply T and s

$M = Ts = 2.626*0.16 = 0.42$

For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is

$L = 40.6 - 0.42 = 40.18$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 40.6 + 0.42 = 41.02$ cm

So

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

3 0

3 years ago