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alexandr1967 [171]
2 years ago
7

Casey has 5/6 left of a section of sidewalk to clean. If he can clean 5/18 of a section in 1 minute, how long will it take him t

o clean what is left?
Mathematics
1 answer:
GaryK [48]2 years ago
7 0

Answer:

Casey will take 3 minutes to clean \frac{5}{6} part of the section.

Step-by-step explanation:

∵ Casey takes the time to cleans \frac{5}{18} of a section = 1 minute

∴ He will take the time to clean complete section = \frac{1}{\frac{5}{18} }

                                                                                  = 1\times \frac{18}{5}

                                                                                   = 3.6 minutes

Now time taken to clean \frac{5}{6} part of the section = \frac{5}{6}\times 3.6

                                                                            = 3 minutes

Therefore, left part of the section will be cleaned by Casey in 3 minutes.

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Is 18-35 an expression or an equation
allsm [11]

Answer:

It is an expression

Step-by-step explanation:

An equation needs to have an equal sign in it and 18-35 doesn't  have an equal sign

Hope this helps!! :)

6 0
3 years ago
Read 2 more answers
LMNP is a rectangle. If LN = 9x – 14 and MP = 7x + 4, find the values of x, LN, and MP.
Fittoniya [83]
I am thinking of a rectangle that has the two sides parallel to one another. Set the two functions equal to one another, so

9x-14=7x+4

After a bunch of algebra and math magic, 2x=18 => x=9

So if you just insert 9 into both equations, both will end up with a value of 67, so it ends up looking like a right triangle. Don't do that. Instead, to find the rectangle widths, use 9x-4 (+10 added to intercept) instead, while keeping 7x+4, so that the intercepts match.

LN) 9x-4 = 9(9)-4 = 81-4 = 77
MP) 7(9)+4 = 63+4 = 67

*If you are also looking for the diagonals, use Pythagorean Theorem 77^2+67^2=(hypotenuse)^2*
7 0
2 years ago
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
zheka24 [161]
<h2>Hello!</h2>

The answer is:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance which is equal to 264 miles of distance in 2 hours + 45 minutes, we  have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation, we have:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

We have that the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

Hence, we have that:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

4 0
3 years ago
Read 2 more answers
Inaaya has a jar of coins containing only nickels, dimes, and quarters. A nickel is worth 5 cents, a dime is worth 10 cents, a q
Verdich [7]

Answer: 91 coins

9 x 25 = 2.25 dollars
3 x 10 = 30 cents
1 x 5 = 5 cents

5 0
2 years ago
Can someone explain this to me​
MA_775_DIABLO [31]
The answer is -4(3n+5)
4 0
2 years ago
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