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3 years ago

Solve the rational equation: 7 - 2/x = 4 + 10/x

Mathematics

2 answers:

iogann1982 [59]3 years ago

8 0

Answer:

x=4

Step-by-step explanation:

-12/x=-3

12=3x

3x=12

x=4

vlabodo [156]3 years ago

7 0

Answer:

7 - 2 / x = 4 + 10 / x

or , 7 - 4 = 10 / x + 2 / x

or , 3 = 12 / x

or , x = 12 / 3

Therefore , x = 4

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1. Find m

Bess [88]

It's forming a circle so we know that together it's going to add up to 360. #1 is 66 because angle A trough E is straight and we have 90 on angle ACF and it's vertical to angle FCG. #2 is 125 because angle ACB is 24 because it's vertical to angle GCE. #3 is 114 because 90 and 24 is 114. #4 is 156 because 66 and 90 equal 156.
1. FCG = 66
2. BCD = 125
3. FCB = 114
4. ACG = 156

4 0

4 years ago

Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

$\frac{1}{2} = e^{19k}$

$0.5 = e^{19k}$

Taking ln both sides,

$\ln(0.5) = \ln(e^{19k})$

$\ln(0.5) = 19k$

$\implies k = \frac{\ln(0.5)}{19}\approx -0.03648$

Now, if the substance to decay to 78% of its original amount,

Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

$0.78 A_0=A_0 e^{-0.03648t}$

$0.78 = e^{-0.03648t}$

Again taking ln both sides,

$\ln(0.78) = -0.03648t$

$-0.24846=-0.03648t$

$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0

3 years ago

Please answer thanks a lot!

Evgen [1.6K]

Vol (pyr) = 1/3 b × h, where h = 15 and b = base = area of triangular base = 1/2 b×h, where h = 12 and b = 13
V = 1/3 (1/2×12×13)×15
V = (1/3×1/2×12)×13×15
V = 2×13×15 = 30×13 = 390 in^3

6 0

4 years ago

Write the slope intercept equation of a line which is parallel to y=3x+5 passing through (-6,3). Can anyone please explain with

Eduardwww [97]

Remember that the slope intercept formula is:

y = mx + b

m is the slope

b is the y-intercept

If lines are parallel then they have the same slope (m)

This means that the slope of the line will be 3 :

y = 3x + b

Now we must find b

To do that you must plug in the point the line goes through in the x and y of the equation.

(-6, 3)

3 = 3(-6) + b

3 = -18 + b

21 = b

y = 3x + 21

Hope this helped!

~Just a girl in love with Shawn Mendes

5 0

3 years ago

Read 2 more answers

Helppp.... don’t understand

sveticcg [70]

The answer is C.

Steps:
(6.77 x 10^4) - (5.21 x 10^3)
(6.77 x 10^4) - (.521 x 10^4)
6.77 - .521 = 6.249
(6.249 x 10^4)

Hope this helps

5 0

3 years ago