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Yuri [45]
3 years ago
7

A survey asked 40 students If they play an instrument and if they are in band.

Mathematics
1 answer:
wel3 years ago
3 0

Answer:

352x^2

Step-by-step explanation:

40\times 1.25x\times 2.20x\times 3.2040×1.25x×2.20x×3.20

(40)1.25x2.20x3.20

+ − .   ln > <

× ÷ /   log ≥ ≤

( )    logx = %

1 Take out the constants.

(40\times 1.25\times 2.20\times 3.20)xx(40×1.25×2.20×3.20)xx

2 Simplify  40\times 1.2540×1.25  to  5050.

(50\times 2.20\times 3.20)xx(50×2.20×3.20)xx

3 Simplify  50\times 2.2050×2.20  to  110110.

(110\times 3.20)xx(110×3.20)xx

4 Simplify  110\times 3.20110×3.20  to  352352.

352xx352xx

5 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

​a

​​ x

​b

​​ =x

​a+b

​​ .

352{x}^{2}352x

​2

​​  

Done

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<h3>Answer:  658.3</h3>

==================================================

Explanation:

The adjacent complementary angle to that 28 degree angle is 62 degrees because 62+28 = 90.

If the reference angle is the upper acute angle 62 degrees, then the y is the opposite leg and the side 350 is the adjacent leg.

Use the tangent ratio

tan(angle) = opposite/adjacent

tan(62) = y/350

350*tan(62) = y

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Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.

Answer:

Dale live 315 miles from the mountains

Step-by-step explanation:

Let y be the speed  of Dale to the mountains

Time taken by Dale to the mountains=7 hrs

Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1

Time taken by Dale back home = 5hours

Since it speed increased by 18 miles per hour back home it speed = y+18

So distance traveled home =speed × time = (y+18)5 ...... eqn 2

Since distance cover is same in both the eqn 1 and eqn 2.

Eqn 1 = eqn 2

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= 7y eqn 1

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