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ch4aika [34]
3 years ago
6

I need this please help mee ​

Mathematics
1 answer:
zubka84 [21]3 years ago
3 0

Answer:

A, 120.

Step-by-step explanation:

x-15+75=180

x+60=180

x=120.

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Which is the graph of the equation y-1=2/3(x-3)
Alexxandr [17]

The attachment is the graph of the equation y - 1 = 2 / 3 (x - 3)

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You are debating about whether to buy a new computer for $800.00 or a refurbished computer with the same equipment for $640.00.
liraira [26]

APR refers to annual interest rate i e 4.5%

Difference:-

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Now

Interest:-

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Remember the code:-

  • Question's calculations mostly given in its options
4 0
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Michael cycled a distance of 12 5/6 miles in 2/3 hours. What is his cycling unit rate in miles per hour?
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19 1/2 miles per hour
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3 years ago
A new crew of painters takes two times as long as the old painters. Together they can paint in 6 hours. How many hours does it t
babymother [125]
Let n be old painters time. Then the new painters are 2n. So:
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3 0
3 years ago
Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th
xenn [34]

Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is \bold{W=-3e^{7x}}

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|

Thus replacing the functions of the exercise we get:

W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|

Working with the determinant we get

W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

3 0
3 years ago
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