(Remember, PEMDAS)
First find what 5^2 equal to
5 • 5 = 25
Then add 25 to 3
25 + 3 = 28
So Oc. :)
Answer:
The dimensions of rectangular fence are 14 feet and 20 feet.
Step-by-step explanation:
We are given the following in the question:
Length of rectangular fence = 14 feet
Width of fence = (14+x) feet
Area of rectangular field = 280 square feet
Area of rectangular field =
Putting the values, we get,
Thus, the dimensions of rectangular fence are 14 feet and 20 feet.
IQR = 40
1) Put the numbers in order: 40, 45, 50, 60, 60, 75, 90, 90, 120
2) Find the median: Median is 60 (the 2nd one)
3) Place parentheses around the numbers above and below the median. For easy identification of Q1 and Q3. (40, 45, 50, 60,) 60, (75, 90, 90, 120)
4) Find the Q1 and Q3. Q1 = median of the lower half of the data; Q3 = median of the higher half of the data. Q1 and Q3 have even sets so its median cannot be defined.
5) Had both sets contain odd sets, the median of Q1 is subtracted from the median of Q3 to get the IQR.
We can then use the Alternative definition of IQR.
IQR is the difference between the largest and smallest values in the middle 50% of a set data.
40, 45, 50, 60, 60, 75, 90, 90, 120
Middle 50% is 50, 60, 60, 75, 90; IQR = Largest value - smallest value;
IQR = 90 - 50 = 40
Do a proportion. 41/100= 83/x. Now cross multiply and divide. 83 x 100= 8300 , 8300 divided by 41= 202.439 (I would just round it to nearest tenth). Answer is 202.4
