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Varvara68 [4.7K]
2 years ago
12

Three vans can carry 18 adults. How many adults are in 7 vans?

Mathematics
2 answers:
Goshia [24]2 years ago
8 0

Answer:

42

Step-by-step explanation:

18/3= 6

6x7= 42

Lady_Fox [76]2 years ago
3 0

Answer:

42 with u need me to explain just say it in the comments :) hope this help

Step-by-step explanation:

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Find an explicit rule for the nth term of the sequence.The second and fifth terms of a geometric sequence are 18 and 144, respec
vova2212 [387]

Given:

second term = 18

fifth term = 144

The nth term of a geometric sequence is:

\begin{gathered} a_n\text{ = ar}^{n-1} \\ Where\text{ a is the first term} \\ r\text{ is the common ratio} \end{gathered}

Hence, we have:

\begin{gathered} \text{ar}^{2-1}\text{ = 18} \\ ar\text{ = 18} \\  \\ ar^{5-1}=\text{ 144} \\ ar^4\text{ =144} \end{gathered}

Divide the expression for the fifth term by the expression for the second term:

\begin{gathered} \frac{ar^4}{ar}\text{ = }\frac{144}{18} \\ r^3\text{ = }\frac{144}{18} \\ r\text{ = 2} \end{gathered}

Substituting the value of r into any of the expression:

\begin{gathered} ar\text{ =  18} \\ a\text{ }\times\text{ 2 =  18} \\ Divide\text{ both sides by 2} \\ \frac{2a}{2}\text{ =}\frac{18}{2} \\ a\text{ = 9} \end{gathered}

Hence, the explicit rule for the sequence is:

a_n\text{ = 9\lparen2\rparen}^{n-1}

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Four speed skaters, Marco, Naim, Oliver, and Pedro, compete in a relay race where they all agree that Naim will be the last
allochka39001 [22]

Answer:

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Step-by-step explanation:

Everyone has already agreed that Naim would be the last skater, so we have to make sure that the result has 'N' in each last place. As we can see, they all have this.

Now, we also have to make sure Oliver <u>not</u> first, because although they're trying to decide, the problem asks for the <u>complement</u> in which "Oliver is the first skater in the race."

A complement is all the values that are NOT in the set, so it cannot be A = {OPMN, OMPN) or A = {MOPN,MPON, OPMN, POMN), because they both have at least one case where 'O' is first.

A complement is ALL other values of the set, so it cannot be A = {MOPN, PMON}, because that set only shows two possible values.

Therefore, A = {MOPN, MPON, PMON, POMN} is your answer.

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