Answer:
7v^3+3v^2-9v
Step-by-step explanation:
This is the simplified version
Answer: X = kuv/ (u+v)
that means that x(u+v)/(uv) = k, a constant. so you want x such that,
x(3+3)/(3*3) = 3(3+1)/(3*1)
x=6
30 b/c 60 x 1/2= 30
Answer= 30
Answer: x=2
Step-by-step explanation:
Expand.
32−8x=7x+2
Add 8x to both sides.
32=7x+2+8x
Simplify 7x+2+8x7x+2+8x to 15x+215x+2.
32=15x+2
Subtract 22 from both sides.
32−2=15x
Simplify 32−2 to 30.
30=15x
Divide both sides by 15.
30/15=x
Simplify 30/15 to 2
2=x
Switch sides.
x=2
Answer:
1st problem: b) 
2nd problem: c) 
Step-by-step explanation:
1st problem:
The formula/equation you want to use is:

where
t=number of years
A=amount he will owe in t years
P=principal (initial amount)
r=rate
n=number of times the interest is compounded per year t.
We are given:
P=2500
r=12%=.12
n=12 (since there are 12 months in a year and the interest is being compounded per month)

Time to clean up the inside of the ( ).


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2nd Problem:
Compounded continuously problems use base as e.

P is still the principal
r is still the rate
t is still the number of years
A is still the amount.
You are given:
P=2500
r=12%=.12
Let's plug that information in:
.