Answer:
95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C
Step-by-step explanation:
The confidence interval for a proportion is given as [p +/- margin of error (E)]
p is sample proportion = 870/1,100 = 0.791
n is sample size = 1,100
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (z) at 5% significance level is 1.96.
E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024
Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767
Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815
95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.
3
1.5 and 4.5 all are divisible by 1.5. Then you just have to find another number that is as well. I chose 3. Theres also 6, 7.5,9,10.5,12
The expression which represents the function required to be generated; (f +g)(x) as in the task content is; 13x -2.
<h3>What is the expression which represents the function required?</h3>
It follows from the function definitions in the task content that the functions given are;
f(x) = 4x +5
g(x) = 9x -7
Hence, the value of (f +g)(x) = f(x) + g(x) and ultimately;
= 4x +5 + 9x -7
= 13x -2
Read more on functions;
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I think 34? because 34 x 2 equals 68, but 35 x 2 is 70?
