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3 years ago

What is the slope of line that passes through the points

Mathematics

1 answer:

mariarad [96]3 years ago

3 0

Answer:

m = -3.6 / -9.5 = 0.37895

Step-by-step explanation:

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What is the final cost for an item that cost $30 and has a tax rate of 7%?<br> *

AVprozaik [17]

Answer:

32.10

Step-by-step explanation:

7% = 0.07

30 x 0.07=2.10

30+ 2.10=32.10

Price before Taxes: $ 30.00

+ Sales Tax (7%): $ 2.10

Total Price with Tax: $ 32.10

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3 years ago

What is the definition of Absolute value and how do you find Absolute Value?

rusak2 [61]

Absolute Value. The absolute value of a number is its distance from zero on the number line. For example, -7 is 7 units away from zero, so its absolute value would be 7.

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3 years ago

Read 2 more answers

Chris plotted 3 points on the graph of the equation y=2x. Which coordinates name the points on Chris’s graph?

Makovka662 [10]

Answer:

(0,0) (2,4) (-2,-4)

Step-by-step explanation:

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3 years ago

What is the explicit rule for the arithmetic sequence shown in the graph?

Afina-wow [57]

Answer:

Step-by-step explanation:

Looking at the given graph, the slope of the line is expressed as

Slope = (y2 - y1)/(x2 - x1)

y2 = 19.5

y1 = 9.5

x2 = 6

x1 = 1

Slope = (19.5 - 9.5)/(6-1)

Slope = 10/5 = 2

The successive terms is increasing by 2

The formula for the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a is the first term of the sequence

n is the number of terms in the sequence.

d is the common difference.

From the information given,

a = 9.5

Tn = an

d = 2

The explicit rule for the arithmetic sequence will be

an = 9.5 + 2(n-1)

8 0

3 years ago

raph the equation with a diameter that has endpoints at (-3, 4) and (5, -2). Label the center and at least four points on the ci

andreyandreev [35.5K]

Answer:

Equation:

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

The point (0,-5), (0,7), (5,0) and (-7,0)also lie on this circle.

Step-by-step explanation:

We want to find the equation of a circle with a diamterhat hs endpoints at (-3, 4) and (5, -2).

The center of this circle is the midpoint of (-3, 4) and (5, -2).

We use the midpoint formula:

$( \frac{x_1+x_2}{2}, \frac{y_1+y_2,}{2} )$

Plug in the points to get:

$( \frac{ - 3+5}{2}, \frac{ - 2+4}{2} )$

$( \frac{ -2}{2}, \frac{ 2}{2} )$

$( - 1, 1)$

We find the radius of the circle using the center (-1,1) and the point (5,-2) on the circle using the distance formula:

$r = \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }$

$r = \sqrt{ {(5 - - 1)}^{2} + {( - 2- - 1)}^{2} }$

$r = \sqrt{ {(6)}^{2} + {( - 1)}^{2} }$

$r = \sqrt{ 36+ 1 } = \sqrt{37}$

The equation of the circle is given by:

$(x-h)^2 + (y-k)^2 = {r}^{2}$

Where (h,k)=(-1,1) and r=√37 is the radius

We plug in the values to get:

$(x- - 1)^2 + (y-1)^2 = {( \sqrt{37}) }^{2}$

$(x + 1)^2 + (y - 1)^2 = 37$

We expand to get:

${x}^{2} + 2x + 1 + {y}^{2} - 2y + 1 = 37$

${x}^{2} + {y}^{2} + 2x - 2y +2 - 37= 0$

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

We want to find at least four points on this circle.

We can choose any point for x and solve for y or vice-versa

When y=0,

${x}^{2} + {0}^{2} + 2x - 2(0) - 35= 0$

${x}^{2} +2x - 35= 0$

$(x - 5)(x + 7) = 0$

$x = 5 \: or \: x = - 7$

The point (5,0) and (-7,0) lies on the circle.

When x=0

${0}^{2} + {y}^{2} + 2(0) - 2y - 35= 0$

${y}^{2} - 2y - 35= 0$

$(y - 7)(y + 5) = 0$

$y = 7 \: or \: y = - 5$

The point (0,-5) and (0,7) lie on this circle.

3 0

3 years ago