Solve for x:(2 x + 3)/3 - 1 = 10
Put each term in (2 x + 3)/3 - 1 over the common denominator 3: (2 x + 3)/3 - 1 = (2 x + 3)/3 - (3)/3:(2 x + 3)/3 - (3)/3 = 10
(2 x + 3)/3 - (3)/3 = ((2 x + 3) - 3)/3:(-3 + 3 + 2 x)/3 = 10
Add like terms. 3 - 3 = 0:(2 x)/3 = 10
Multiply both sides of (2 x)/3 = 10 by 3/2:(3×2 x)/(2×3) = (3×10)/2
(3×10)/2 = (3×10)/2:(3×2 x)/(2×3) = (3×10)/2
(3×2 x)/(2×3) = (2×3)/(2×3)×x = x:x = (3×10)/2
10/2 = (2×5)/2 = 5:x = 3×5
3×5 = 15:Answer: x = 15
The correct answers would be a b and 2 because I don’t know this is a test to be honestly
Answer:1
Step-by-step explanation:
The answer is C, 3325 students.
190 divided by 2 and then multiplied by 35.
Answer: D) cube root of 16
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Explanation:
The rule we use is
![x^{m/n} = \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7Bm%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D)
In this case, x = 4, m = 2 and n = 3.
So,
![x^{m/n} = \sqrt[n]{x^m}\\\\\\4^{2/3} = \sqrt[3]{4^2}\\\\\\4^{2/3} = \sqrt[3]{16}\\\\\\](https://tex.z-dn.net/?f=x%5E%7Bm%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%5C%5C%5C%5C%5C%5C4%5E%7B2%2F3%7D%20%3D%20%5Csqrt%5B3%5D%7B4%5E2%7D%5C%5C%5C%5C%5C%5C4%5E%7B2%2F3%7D%20%3D%20%5Csqrt%5B3%5D%7B16%7D%5C%5C%5C%5C%5C%5C)
Showing that the original expression turns into the cube root of 16.
