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laila [671]
3 years ago
14

A pole that is 3m tall casts a shadow that is 1.3m long. At the same time, a nearby building casts a shadow that is 41.75m long.

How tall is the building? Round your answer to the nearest meter.
Mathematics
1 answer:
8090 [49]3 years ago
6 0

Answer:We're looking for a,b such that

\dfrac{9x-20}{(x+6)^2}=\dfrac a{x+6}+\dfrac b{(x+6)^2}

Step-by-step explanation:

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The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of
Lilit [14]

Check the picture below.

\bf (\stackrel{a}{1}~,~\stackrel{b}{-1})\qquad \impliedby \textit{let's find the hypotenuse} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c = \sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{1^2+(-1)^2}\implies c=\sqrt{2} \\\\[-0.35em] ~\dotfill

\bf sin(\theta ) \implies \cfrac{\stackrel{opposite}{-1}}{\stackrel{hypotenuse}{\sqrt{2}}}\implies \cfrac{-1}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies -\cfrac{\sqrt{2}}{(\sqrt{2})^2}\implies -\cfrac{\sqrt{2}}{2}

\bf cos(\theta ) \implies \cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{\sqrt{2}}}\implies \cfrac{1}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies \cfrac{\sqrt{2}}{(\sqrt{2})^2}\implies \cfrac{\sqrt{2}}{2} \\\\\\ tan(\theta ) = \cfrac{\stackrel{opposite}{-1}}{\stackrel{adjacent}{1}}\implies tan(\theta ) = -1

7 0
3 years ago
Read 2 more answers
Sarah is wrapping the rectangular prism box for her Valentine. She calculated how many square meters of wrapping paper she would
AnnyKZ [126]

Answer:

She probably was supposed to multiply, instead of add.

Step-by-step explanation:

First multiply 24 and 32, which is 768.

Second multiply 768 and 12, which is 9216

9216 is the answer.

7 0
2 years ago
Simplify (3^3*5^3)^-2
Juliette [100K]
(3³ x 5³)² - 2 

( 27 x 125)
² - 2 

125 x 27 = 3375

3375
² = 11,390,625

11,390,625 - 2 = 11,390,623


4 0
3 years ago
Write a two-step equation from the verbal model.
Fiesta28 [93]

Answer:

I'm sorry but, this is confusing the way that you put it.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find two consecutive integers whose product is 24 more than three times the first integer
gregori [183]
X= first integer
x+1= second consecutive integer

Product means multiply, so we'll multiply x by x+1. More than means to add and 3 times is multiplication.

x(x + 1)= 3x + 24
use distributive property to multiply x by everything in parentheses
(x*x) + (x*1)= 3x + 24
x^2 + x= 3x + 24
subtract 3x from both sides
x^2 - 2x= 24
subtract 24 from both sides
x^2 - 2x - 24= 0
factor the expression
(x-6)(x+4)= 0
x-6=0
x=6

x+4=0
x=-4

If x= 6 is the first integer, x+1= 7 is the second integer

If x= -4 is the first integer, x+1= -3 is the second integer


Hope this helps! :)
7 0
3 years ago
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