In parallelogram ABCD , diagonals AC and BD intersect at point E, BE=2x^2−x , and DE=x^2+6 .
2 answers:
BD=BE+ED=2x²-x+x²+6=3x²-x+6
BE = DE
2x^2-x = x^2+6
x^2-x-6 =0
(x+2) (x-3)
x = -2 or x = 3
1 solution using x = -2:
BE = 2(-2)^2 -(-2) = 10
DE = (-2)^2+6 = 10
10 +10 =20
2nd solution using x = 3
BE =2(3)^2-3 = 15
DE = (3)^2+6 =15
15+15 = 30
The answer could be 20 or 30. Will need to try them both
Would probably try 30 first ( maybe x can't be a negative number?)
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