D 1 unit : 10,5 wonwnwwnd dnkennednen sddd cddd
Answer:
The property shown in matrix addition given is "Additive Inverse Property"
Step-by-step explanation:
First of all lets define what a matrix is.
A matrix is an array of rows and columns that consists of numbers. There are several types of matrices. The one in our question is a row matrix which consists of only one row.
There are several addition properties for matrices.
One of them is additive inverse property. The additive inverse of a matrix consists of the same elements but their signs are changed.
Additive inverse property states that the sum of a matrix and its additive inverse is a zero matrix.
![\left[\begin{array}{ccc}-6&15&-2\end{array}\right] + \left[\begin{array}{ccc}6&-15&2\end{array}\right] = \left[\begin{array}{ccc}0&0&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%2615%26-2%5Cend%7Barray%7D%5Cright%5D%20%2B%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-15%262%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%260%5Cend%7Barray%7D%5Cright%5D)
Hence,
The property shown in matrix addition given is "Additive Inverse Property"
The average rate of change of the function will be 63.
The average rate of change of the function is used to find the slope of the graphed function which can be calculated by the change in y value divided by the change in x value.
The average rate of change of function f(x) in the interval [a,b] can be calculated as avearge rate of change= (f(b)- f(a))/(b-a)
Here given function is g(x) = 7x³-4
which is defined in the interval [-3,3].
So using the defination of the average rate of change, The average rate of change= (g(3)-g(-3))/(3-(-3))
= {(7(3³)-4)-(7*(-3)³-4)}/(3-(-3))
= {(189-4)-(-189-4)}/(3+3)
= (185-(-193))/6
= (185+193)/6
= 378/6
= 63
Therefore the average rate of change of the function will be 63.
Learn more about the average rate of change function
here: brainly.com/question/10208814
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X<span> 3</span><span> + 3x</span><span> 2</span><span> + 9x + 27 R88 is the answer</span>
Use the Pythagorean theorem since you are working with a right triangle:
a^2+b^2=c^2a2+b2=c2
The legs are a and b and the hypotenuse is c. The hypotenuse is always opposite the 90° angle. Insert the appropriate values:
0.8^2+0.6^2=c^20.82+0.62=c2
Solve for c. Simplify the exponents (x^2=x*xx2=x∗x ):
0.64+0.36=c^20.64+0.36=c2
Add:
1=c^21=c2
Isolate c. Find the square root of both sides:
\begin{gathered}\sqrt{1}=\sqrt{c^2}\\\\\sqrt{1}=c\end{gathered}1=c21=c
Simplify \sqrt{1}1 . Any root of 1 is 1:
c=c= ±11 *
c=1,-1c=1,−1
