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Given the foci of (8,0) and the difference of the focal radii = 6, find the equation of the hyperbola

k0ka [10]

Given :

The foci of hyperbola are (8,0) and (-8,0) .

The difference of the focal radii = 6.

To Find :

The equation of the hyperbola.

Solution :

We know, distance between foci is given by :

2c = 8 - (-8)

c = 8

Also, difference between the foci or focal distance is given by :

2a = 6

a = 3

Now, we know for hyperbola :

$b^2 +a^2 = c^2\\\\b^2={c^2-a^2}\\\\b^2 = 64-9\\\\b^2 = 55$

General equation of hyperbola is :

$\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\\\\\dfrac{x^2}{9}+ \dfrac{y^2}{55}=1$

Hence, this is the required solution.

3 0

3 years ago

Round 95.9153055893 to the nearest tenth

Oksana_A [137]

Answer:

100

Step-by-step explanation:

6 0

3 years ago

Thaddeus models the number of hours of daylight in his town as

AfilCa [17]

Option (A) : least: 10 hours; greatest: 14 hours

The function f(x) = sin x has all real numbers in its domain, but its range is

−1 ≤ sin x ≤ 1.

How to solve such range questions?

Such questions in which every term is in addition and its range is asked is simplest ones to solve if we know the range of each of term. This can be seen from this question

Given: d(t) = 2sin(xt) + 12

= −1 ≤ sin (xt) ≤ 1.

= −2≤ 2 sin (xt) ≤ 2.

= 10 ≤ 2sin (xt) + 12 ≤ 14

= 10 ≤d(t) ≤ 14

Thus least: 10 hours; greatest: 14 hours

Learn more about range of trigonometric ratios here :

brainly.com/question/14304883

#SPJ4

6 0

2 years ago

Please assist me with the domain and range of graphs

Sphinxa [80]

Answer: see below

Step-by-step explanation:

Domain represents the x-values from the smallest (furthest left) to the biggest (furthest right).

Range represents the y-values from the lowest (furthest down) to the highest (furthest up).

Interval notation: If a value is included (closed dot), use a bracket [ ]

If a value is NOT included (open dot), use a parenthesis ( )

Note that ± ∞ is never included.

1. Domain: smallest x-value is -4 (included). biggest x-value is 3 (included)

Range: lowest y-value is 2 (included). highest y-value is 5 (included)

D: x = [-4, 3] R: y = [2, 5]

2. Domain: smallest x-value is -∞ (←). biggest x-value is 2 (included)

Range: lowest y-value is 2 (included). highest y-value is ∞ (↑)

D: x = (-∞, 2] R: y = [2, ∞)

3. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

Range: lowest y-value is -∞ (↓). highest y-value is ∞ (↑)

D: x = (-∞, ∞) R: y = (-∞, ∞)

4. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

Range: lowest y-value is -∞ (↓). highest y-value is 4 (included)

D: x = (-∞, ∞) R: y = (-∞, 4]

5. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

Range: lowest y-value is 3 (included). highest y-value is ∞ (↑)

D: x = (-∞, ∞) R: y = [3, ∞)

6. Domain: smallest x-value is -2 (included). biggest x-value is ∞ (→)

Range: lowest y-value is -3 (included). highest y-value is ∞ (↑)

D: x = [-2, ∞) R: y = [-3, ∞)

4 0

3 years ago

Pls, can someone answer this, Explain, using words and numbers, how to subtract 7x - ( 6x + 13). Remember to include the solutio

Hitman42 [59]

So first you distribute the negative to the 6x and 13 which will flip the sign of both of them to -6x and -13 so take away the parentheses and the equation is now 7x-6x-13. You combine the x’s and you get 1x-13 or x-13

3 0

3 years ago