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Keith_Richards [23]

3 years ago

12

NO SILLY ANSWERS PLEASE Can someone help me with this?

1 answer:

marusya05 [52]3 years ago

7 0

Keep in mind that, when the logarithm base is not explicitly written, base 10 is assumed, therefore,

$\bf \textit{Logarithm Cancellation Rules}\\\\
log_a a^x\implies x\qquad \qquad a^{log_ax}=x\\\\
-------------------------------\\\\
10^{log(3)}+log(100)\implies 10^{log_{10}(3)}+log_{10}(100)\implies 3+log_{10}(10^2)
\\\\\\
3+2\implies 5$

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Fred is making a fruit salad the ratio of cups of peaches to cups of cherries is 2:3 how many cups of peaches will feed need to

Law Incorporation [45]

Answer:

24 cupsnof peaches

Step-by-step explanation:

The question says that Fred is making a fruit salad the ratio of cups of peaches to cups of cherries is 2:3 how many cups of peaches will feed need to make 60 cups of fruit salad

---Since both of them share the ratio of 2:3,them we can find out the number of cup of peaches required to make 60 cups of salad.

The ratio of peaches is 2

While that of cherries is 3

--- sum of their ratios is 5

For peaches,it will be

2/5 × 60 = 120/5

= 24 cups of peaches

7 0

3 years ago

Question 78 find the value of x

gladu [14]

For this case we have that by definition, the volume of a parallelepiped is given by:

$V = l * w * h$

Where:

l: It's the long

w: It is the width

h: It's the height

From the figure we have the following data:

$V = 975 \ ft ^ 3\\h = 9 \ ft\\w = 4ft\\x =?$

We must find the value of the length of the parallelepiped:

$975 = x * 4 * 9\\975 = 36x\\x = \frac {975} {36}\\x = 27.083$

Answer:

$x = 27.1 \ ft$

5 0

3 years ago

In a horse race with 5 horses, you make a bet by predicting the ranking of all 5 horses. Suppose you place your bet at random. W

lapo4ka [179]

Answer:

P( top two horses are predicted incorrectly in incorrect order)

= $\frac{1}{2}$

Step-by-step explanation:

In the horse race the outcome can be predicted in 5! = 120 ways.

Now suppose the top two horses were predicted incorrectly in incorrect order. Now, the top horse can be predicted incorrectly in 4 ways.

Suppose the top horse was predicted to be in k-th position where k = 2, 3 ,4,5

so the second horse can be predicted to be in place from 1 to (k - 1)

So, the top two horses can be predicted incorrectly in incorrect order

in $\sum_{k =2}^{5}(k - 1)$ = 10 ways

and for each prediction of the two the remaining horses may be predicted in 3! = 6 ways.

Hence ,

P( top two horses are predicted incorrectly in incorrect order)

= $\frac{6 \times 10}{120}$

= $\frac{1}{2}$

8 0

3 years ago

HELP ME PLEASE!!!! I NEED HELP!!!!!

ehidna [41]

I'm pretty sure the answer is A. hope that helped

8 0

3 years ago

Read 2 more answers

Can someone help it’s due in 40mins!!

Lorico [155]

Answer:

Step-by-step explanation:

$\frac{8}{32} = \frac{4}{16} = \frac{2}{8} = \frac{1}{4}$

$\frac{27}{54} = \frac{9 }{18} = \frac{3}{6} = \frac{1}{2}$

$\frac{36}{24} = \frac{18}{12} = \frac{9}{6} = \frac{3}{2}$

$\frac{30}{60} = \frac{15}{30} = \frac{5}{10} = \frac{1}{2}$

8 0

3 years ago