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3 years ago

Help as fast as u can

Mathematics

1 answer:

lyudmila [28]3 years ago

8 0

I believe the answer to your question is going to be

D) g(x)=(x+3)^2

Hope I’m correct!

You might be interested in

Assume a bank loan requires an interest payment of $85 per year and a principal payment of $1,000 at the end of the loan's eight

Alex

Answer:

$919.98

Step-by-step explanation:

To solve using a financial calculator do

N=8

I/Y=10

PMT=85

FV=1000

CMPT PV get 919.98

To do by hand find the present value of the interst payments

85*(1-(1/1.1)^8)

which is 453.4687

Find the present value of the final ballon payment

1000*(1/1.1)^8

which is 466.507

take the sum

466.507+453.4678= 919.98

3 0

3 years ago

Please answer both ASAP (middle school) (probability)

lana66690 [7]

Answer:

the first one is 18/32 and the second one is 125 games or 120

Step-by-step explanation:

for the first add all the numbers to get your denominator then add the probability of green aND YELLOW.

for the second you just divide 200 by eight to get 25 then times 25 by 5 to get your anwser

hope this helped :)

7 0

3 years ago

Jan has $245.50 to spend on home repairs. The repairman charges $75 for the initial visit and $35 per hour or any part of an hou

Murrr4er [49]

Answer:

Step-by-step explanation:

4 0

3 years ago

Jennifer utilizo 2/7 de metro de cinta para hacer moños para sus primas. Ahora le quedan 10/21 de metro de cinta. ( problema ver

Vikki [24]

Answer:

$x = \frac{16}{21}\,m$

Step-by-step explanation:

El enunciado pregunta la cantidad inicial de cinta utilizada por Jennifer, la cual es la suma de la porción utilizada y la porción remanente:

$x = \frac{2}{7}\,m + \frac{10}{21}\,m$

$x = \frac{42}{147}\,m + \frac{70}{147}\,m$

$x = \frac{112}{147}\,m$

$x = \frac{16}{21}\,m$

6 0

3 years ago

I need the answer for this problem please

Savatey [412]

Answer:

Step-by-step explanation:

Find all probabilities:

A. False

$Pr(\text{red shirt}|\text{large shirt})=\dfrac{\text{number red large shirts}}{\text{number large shirts}}=\dfrac{42}{77}=\dfrac{6}{11}\\ \\Pr(\text{large shirt})=\dfrac{\text{number large shirts}}{\text{number shirts}}=\dfrac{77}{165}=\dfrac{7}{15}$

B. True

$Pr(\text{blue shirt}|\text{large shirt})=\dfrac{\text{number blue large shirts}}{\text{number large shirts}}=\dfrac{35}{77}=\dfrac{5}{11}\\ \\Pr(\text{blue shirt})=\dfrac{\text{number blue shirts}}{\text{number shirts}}=\dfrac{75}{165}=\dfrac{5}{11}$

C. False

$Pr(\text{shirt is medium and blue})=\dfrac{\text{number medium and blue shirts}}{\text{number shirts}}=\dfrac{48}{165}=\dfrac{16}{55}\\ \\Pr(\text{medium shirt})=\dfrac{\text{number medium shirts}}{\text{number shirts}}=\dfrac{88}{165}=\dfrac{8}{15}$

D. False

$Pr(\text{large shirt}|\text{red shirt})=\dfrac{\text{number red large shirts}}{\text{number red shirts}}=\dfrac{42}{90}=\dfrac{7}{15}\\ \\Pr(\text{red shirt})=\dfrac{\text{number red shirts}}{\text{number shirts}}=\dfrac{90}{165}=\dfrac{6}{11}$

4 0

4 years ago