All categories

2 years ago

This is hard can I get help

Mathematics

1 answer:

Eduardwww [97]2 years ago

3 0

Same as the last one you asked.

AB + BC = AC. Just think of it like Part + Part = Whole Thing

(2x + 6) + (6x + 5) = 51

Combine like terms:
8x + 11 = 51

Subtract 11 from both sides to get the variable and its coefficient on its own:
8x = 51 - 11
8x = 40

Divide both sides by 8 to isolate the variable:
x = 5

It's asking for us to find BC so now we plug in x = 5 to the equation it gave for BC.

6x + 5
6(5) + 5
30 + 5
35

BC is 35 units long.

You might be interested in

Can somebody help me please

Mrac [35]

Answer:
A=(1/2)BxH
10x6=60m

4 0

2 years ago

Read 2 more answers

Four times the sum of a number and 15 is at least 120. Let x represent the number. Find all possible values for x.

Aleksandr [31]

4(x + 15) > = 120
4x + 60 > = 120
4x > = 120 - 60
4x > = 60
x > = 60/4
x > = 15...........so ur answer is 15 or more

4 0

2 years ago

John has a boat that will travel at the rate of 15 kph in still water. He can go upstream for 35 km in the same time it takes to

Otrada [13]

Answer:

The boat traveling at 24 kph when John goes downstream.

Step-by-step explanation:

We are given the following in the question:

John has a boat that will travel at the rate of 15 kph in still water.

Let x be the speed of the current.

Speed of boat in upstream

$(15-x)\text{ kph}$

Speed of water in downstream

$(15+x)\text{ kph}$

Relation:

$\text{Speed} = \dfrac{\text{Distance}}{\text{Time}}$

We have to find the speed of boat in downstream.

Time to travel upstream for 35 km = Time to travel 140 km downstream

$\displaystyle\frac{35}{15-x}=\frac{140}{15+x}\\\\35(15+x) = 140(15-x)\\525 + 35x = 2100 - 140x\\175x = 1575\\x = 9$

Thus, speed of current is 9 kph.

Speed of boat in downstream = 15 + 9 = 24 kph.

Thus, the boat traveling at 24 kph when John goes downstream.

4 0

3 years ago

I'm having trouble filling this chart out and need some help please.

777dan777 [17]

Answer:

Figure 1: complementary

figure 2: adjacent

figure 3: supplementary

figure5: supplementary

7 0

2 years ago

Nsider the following system of equations y=6x^2+1, y=x^2+4

sp2606 [1]

The given equations are y= 6x^2+1 and y=x^2+4

Both the equations equal y so we can make them equal

6x^2+1=x^2+4

To bring x term on one side we subtract x^2 both sides

6x^2-x^2+1=4

5x^2+1=4

To isolate x term we subtract 1 both sides

5x^2=4-1

5x^2=3

Dividing by 5 both sides

X^2=3/5

Taking root of both sides we have:

X=±√⅗

Substituting x value to find y

When x=+√⅗=0.7745

Y= 6x^2+1

Y=6(3/5)+1

Y= 18/5+1

Y=23/5 =4.6

When x= -√⅗=-0.7745

Y= 6(3/5)+1

Y=23/5=4.6

Point of intersections are ( 0.7745,4.6) and (-0.7745,4.6)

7 0

2 years ago