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3 years ago

Please help me!!!!!!!!

Mathematics

1 answer:

belka [17]3 years ago

4 0

Answer:

fraction is 75/100

decimal is 0.75

Step-by-step explanation:

because there are 75 of them that are shaded out if 100 so 75/100 and to find out in decimal 75÷100=0.75.

hope this helps u understand:)

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How to do these problems

topjm [15]

$\bf \begin{array}{llcll}
3x-y=7&&3x-y=7\\
x+y=-11&\boxed{\times -3}\implies &-3x-3y=33\\
&&-------\\
&&0-4y=40
\end{array}\\\\
y=\cfrac{40}{-4}\implies y=-10\\\\
-----------------------------\\\\

\begin{array}{cllll}
x-7y=-9\\
-x+8y=10\\
--------\\
0+y=1
\end{array}\\\\
-----------------------------\\\\

\begin{array}{llcll}
7x+y=14&\boxed{\times -3}\implies &-21x-3y=-42\\
8x+3y=16&&8x+3y=16\\
&&--------\\
&&-13x+0=-26
\end{array}
\\\\
x=\cfrac{-26}{-13}\implies x=2$

notice, the 2nd one, had a x and -x, so, we don't have to multiply anything there, just cancel those two out

5 0

3 years ago

A plane is descending towards a runway in Chicago. The plane is flying at an altitude of 7 miles and is 190 miles from the runwa

KengaRu [80]

height = 7 miles, base dimension is 190 miles

to find the angle on the ground up to the plane

use arctan(7/190)

acrtan on a calculator is tan^-1

arctan(7/190) = 2.1099 degrees. Round off as necessary

3 0

3 years ago

Given: 2y"+ 3y' + y = 13x2 Determine yp Determine ye ns ) Determine the general solution satisfying the following conditions: y'

lana66690 [7]

I'm not sure what to make of "yp" and "ye ns", or the given initial conditions, so I'll let you handle that and just focus on the general solution.

$2y''+3y'+y=13x^2$

The corresponding homogeneous ODE has characteristic equation

$2r^2+3r+1=(2r+1)(r+1)=0$

with roots at $r=-\dfrac12$ and $r=-1$ , so the characteristic solution to the ODE is

$y_c=C_1e^{-x/2}+C_2e^{-x}$

For the non-homogeneous ODE, assume a solution of the form

$y_p=ax^2+bx+c$

$\implies{y_p}'=2ax+b$

$\implies{y_p}''=2a$

Substituting $y_p$ and its derivatives into the ODE gives

$2(2a)+3(2ax+b)+(ax^2+bx+c)=13x^2$

$ax^2+(6a+b)x+(4a+3b+c)=13x^2$

$\implies\begin{cases}a=13\\6a+b=0\\4a+3b+c=0\end{cases}\implies a=13,b=-78,c=182$

so that the particular solution is

$y_p=13x^2-78x+182$

and the general solution is

$\boxed{y(x)=C_1e^{-x/2}+C_2e^{-x}+13x^2-78x+182}$

8 0

3 years ago

What is an equation for this line? A) x = 0 B) y = -x C) y = 1 D) y = x

swat32

Answer:

B). y = -x

Step-by-step explanation:

The slope of the line is -1 because from evry point it goes down 1 and to the right one. The y-intercept is 0.

3 0

3 years ago

Read 2 more answers

-6x-10=2 what is x?REMEMBER 6 IS NEGATIVE

lora16 [44]

-2.
You have to get rid of the 10, so you add 10. After you add ten, you add 10 to the 2. Now, your left with -6x=12. -6x divided by -6= 2, so 12–6=-2

6 0

3 years ago