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DedPeter [7]
4 years ago
14

Hey can you please help me posted picture of question

Mathematics
1 answer:
Rudik [331]4 years ago
3 0
Following changes are made in graph of G(x) to obtain F(x)

1) Vertical stretch by a factor of 2
So, G(x) will be changed to 2G(x)

2) Shift towards Right by 2 units
So, 2G(x) will be changed to 2G(x - 2)

3) Upward shift by 2 units.
So, 2G(x - 2) will be changed to 2G(x - 2) + 2

Thus,

F(x) = 2G(x - 2) + 2
F(x) = 2(x - 2)² + 2

Therefore, option C is the correct answer
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A function has y-intercept of -3 and a slope of -7/3. Which equation below describes the function?
Juliette [100K]

Answer:7/8 8/7

Step-by-step explanation:

7 0
3 years ago
A tortoise is walking in the desert. It takes
dlinn [17]

96 meters per hour :)


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If someone can answer this and explain it, I would really appreciate it, thanks.
daser333 [38]

Answer:

x = 13

Step-by-step explanation:

Now since the lines are parrarel, the intersection points are alternate to each other. Therefore, A = B.

Solve:

8x + 2 = 14x - 76

2 + 76 = 6x

78 = 6x

x = 13

8 0
3 years ago
Read 2 more answers
Given y+2x+7, write an equation whose graph is shifted 3 units to the right. Thank you!
ddd [48]

Answer:

y=2x+1

Step-by-step explanation:

To find the answer, first graph the equation and find coordinates for atleast 2 points. We can find (0,7) and (1,9). Next we add 3 to the x coordinate of each point. We get (3,7) and (4,9). We know the slope which is 2. So our equation becomes y=2x+b. Next we substitube a coordinate pair, with y and x in the equation. We get 7=2*3+b. Solve and we get 1=b.

Therefore,

y=2x+1.

I hope this helps.

6 0
3 years ago
Vectors: Find the vector from the point A=(−1,−7,3) to the point B=(3,−2,9).
devlian [24]

Answer:

\overrightarrow {AB} = (4,5,6)

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

Step-by-step explanation:

The vector AB is the vectorial difference between point A and B, that is:

\overrightarrow {AB} = \vec B - \vec A

Given that \vec A = (-1,-7,3) and \vec B = (3,-2,9), the vector AB is:

\overrightarrow {AB} = (3,-2,9)-(-1,-7,3)

\overrightarrow{AB} = (3-(-1),-2-(-7),9-3)

\overrightarrow {AB} = (4,5,6)

The vectorial equation of the line is represented by:

\langle x, y, z\rangle = \vec A + t \cdot \overrightarrow {AB}

Where t is the parametric variable, dimensionless. Given that \vec A = (-1,-7,3) and \overrightarrow {AB} = (4,5,6)

\langle x,y,z \rangle = \langle -1,-7,3 \rangle + t\cdot \langle 4,5,6 \rangle

Finally, the list of questions are now checked:

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

4 0
3 years ago
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