Question

PLEASE HELP 8 ml of a 80% acid solution was mixed with 12 ml of a 20% acid solution. What is the percentage of acid in the new solution?

Answer 1

Answer:

44%

Step-by-step explanation:

So you have 2 bottles. One bottle is 8ml and is 80% acid. the other is 12 ml and is 20% acid.

This means there's 6.4 ml of acid in bottle 1(8*0.8) and 2.4 ml of acid in the other one(12*0.2).

The total amount of liquid is 8+12 = 20

The total amount of acid is 6.4+2.4 = 8.8

Percentage of acid in the new solution is 8.8/20 = 0.44 = 44%