Answer:
Rate = 4.5
Step-by-step explanation:
It is given that,
A cookie recipe calls for 1/3 of a cup of sugar and 1 1/2 cups of flour.
We need to find the unit rate of flour to sugar for the cookie recipe. It can be calculated as follows :
So, the unit rate of flour to sugar for the cookie recipe is 4.5
Answer:
The points for the given two linear equation as
= - 2 , - 6
= - 2 , 6
The graph so plotted as shown
Step-by-step explanation:
Given as :
The two linear equation are
y = 3 x ........A and
y = - x - 8 .........B
Solving equation A and B
Now, Put The value of y from eq A into eq B
So, 3 x = - x - 8
Or, 3 x + x = - 8
Or, 4 x = - 8
∴ x = 
I.e x = - 2
Now , Put the value of x into eq A
∵ y = 3 x
∴ y = 3 × (-2)
I.e y = - 6
Again, Put the value of x into eq B
∵ y = - x - 8
∴ y = - 2 - (-8)
I.e y = 6
So, for x = - 2 , y = - 6
And for x = - 2 , y = 6
Hence , The points for the given two linear equation as
= - 2 , - 6
= - 2 , 6
The graph so plotted as shown . Answer
First, let's calculate the mean and the mean absolute deviation of the first bowler.
FIRST BOWLER: <span>8,5,5,6,8,7,4,7,6
Mean = (Sum of all data)/(Number of data points) = (8+5+5+6+8+7+4+7+6)/9
<em>Mean = 6.222</em>
Mean absolute deviation or MAD = [</span>∑(|Data Point - Mean|]/Number of Data Points
MAD = [|8 - 6.222| + |5 - 6.222| + |5 - 6.222| + |6 - 6.222| + |8 - 6.222| + |7 - 6.222| + |4 - 6.222| + |7 - 6.222| + |6 - 6.222|]/9
<em>MAD = 1.136</em>
SECOND BOWLER: <span>10,6,8,8,5,5,6,8,9
</span>Mean = (Sum of all data)/(Number of data points) = (<span>10+6+8+8+5+5+6+8+9</span>)/9
<em>Mean = 7.222</em>
Mean absolute deviation or MAD = [∑(|Data Point - Mean|]/Number of Data Points
MAD = [|10 - 7.222| + |6 - 7.222| + |8 - 7.222| + |8 - 7.222| + |5 - 7.222| + |5 - 7.222| + |6 - 7.222| + |8 - 7.222| + |9 - 7.222|]/9
<em>MAD = 1.531
</em>
The mean absolute deviation represents the average distance of each data to the mean. Thus, the lesser the value of the MAD is, the more consistent is the data to the mean. <em>B</em><em>etween the two, the first bowler is more consistent.</em>
1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
Answer:
no change in area
Step-by-step explanation:
The original area is
A = 12*5 = 60 ft^2
The new length and width
l = 12 + .25 (12) = 12+3 =15
w = 5 - .2 (5) =5-1 = 4
The new area is
A = l*w =15*4 = 60 ft^2
The area is the same
