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3 years ago

Put these numbers in order from least to greatest. 1/8,1/2,0.13, and 7/8

Mathematics

2 answers:

never [62]3 years ago

6 0

Step-by-step explanation:

0.13,1/2,1/8,and 7/8

hope it is helpful to you

Alex73 [517]3 years ago

3 0

Answer: 1/8, 0.13, 1/2, 7/8

Step-by-step explanation: Mental Math

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Give the slope of y- 4 = 5(x - 2) and a point on the line.

ValentinkaMS [17]

Answer:

<h2>B. The slope is 5 and (2, 4) is on the line.</h2>

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point

We have the equation:

$y-4=5(x-2)$

Therefore

m = 5

(x₁, y₁) = (2, 4)

5 0

3 years ago

Need help ASAP. Question in photo. Will mark brainliest if correct

ioda

Answer:

Step-by-step explanation:

I did this question today, pls lmk if u get it right

5 0

2 years ago

An oval track is made by erecting semicircles on each end of a 60m by 120m rectangle. Find the length of the track and the area

vodomira [7]

Refer to the figure shown below.

Because the question states that the semi circles are at the ends of the rectangle, each semicircle has a radius of 30 m.

The circumference of the oval is
2π(30) + 2*120 = 60π + 240 m = 428.5 m

The area of the oval is
π(30²) + 60*120 = 900π + 7200 m² = 1.0027 x 10⁴ m²

Note:
If the semi circles are placed on the 120-m sides of the rectangle, then similar calculations yield:
Circumference = 120π + 120 m = 497 m
Area = 3600π + 7200 m² = 1.851 x 10⁴ m²

Answer:
If the semi circles are placed on the 60-m sides of the rectangle, then
Circumference = 60π + 240 m, or 428.5 m
Area = 900π + 7200 m², or 1.0027 x 10⁴ m²

if the semi circles are placed on the 120-m sides of the rectangle, then
Circumference = 120π + 120 m, or 497 m
Area = 3600π + 7500 m², or 1.851 x 10⁴ m²

3 0

3 years ago

On a coordinate grid, AB has an end point B at (24, 16). The midpoint of AB is P(4, -3). What is the y-coordinate of Point A?

inysia [295]

The y-coordinate of point A is -22

Step-by-step explanation:

Given

B = (24,16)

P = (4,-3)

The formula for mid-point of AB will be given by:

$P = (\frac{x_A+x_B}{2} , \frac{y_A+y_B}{2})$

As we already know the y-coordinate of midpoint

We can put the formula's y coordinate equal to the given value

$\frac{y_A+y_B}{2} = -3\\\frac{y_A + 16}{2 } = -3\\y_A+16 = -3 * 2\\y_A +16 = -6\\y_A = -6-16\\y_A = -22$

Hence,

The y-coordinate of point A is -22

Keywords: Mid-point, coordinate geometry

Learn more about coordinate geometry at:

#LearnwithBrainly

7 0

3 years ago

The height h (in feet) of an object dropped from a ledge after x seconds can be modeled by h(x)=−16x2+36 . The object is dropped

kakasveta [241]

Check the picture below.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}$

so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?

$\bf h(x)=-16x^2+36\implies \stackrel{h(x)}{0}=-16x^2+36\implies 16x^2=36 \\\\\\ x^2=\cfrac{36}{16}\implies x^2 = \cfrac{9}{4}\implies x=\sqrt{\cfrac{9}{4}}\implies x=\cfrac{\sqrt{9}}{\sqrt{4}}\implies x = \cfrac{3}{2}~~\textit{seconds}$

now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2 = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill$

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

4 0

3 years ago