Answer:
Step-by-step explanation:
Given that, O is the center of the circle and PQ is a tangent to the circle at point Q. OQ is a radius of the circle.
We know that, a tangent to a circle is a line which just touches the circle. And the angle between the tangent and radius is 90°.
Hence, ΔOQP is a right angle triangle. We know that the sum of the measurements of all the 3 angles of a triangle leads to 180°. So,