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olga2289 [7]
3 years ago
10

Please help due in 5 minutes !

Mathematics
2 answers:
SpyIntel [72]3 years ago
4 0
The first option is correct
Snezhnost [94]3 years ago
3 0

Answer:

Look at the picture given

Step-by-step explanation:

We know that Sonja's house is 4 blocks west and 1 block south from the center while her school is 3 blocks east and 2 blocks north,

Follow NESW rule :

N = Up

E = Right

S = Down

W = Left

To solve this, all we need to is move 4 times to the left and 1 down to determine her house. As for her school, we need to move 3 blocks to the right and move 2 times up.

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Please help , thank you so much !!
Shkiper50 [21]

Answer:

that is scientifically impossible

Step-by-step explanation:

one you can't add, subtract, round up, or use decimals write that down.

3 0
3 years ago
Town C is 2 miles east of town A and 2 miles south of Town B as in the figure at right. which of the following is the best estim
Ray Of Light [21]
Since C is 2mi east of A and 2mi south of B, the shortest distance from A to B would be a straight line which is equal to the hypotenuse of a right triangle with a base of 2mi and a height of 2mi..

d^2=x^2+y^2

d^2=2^2+2^2

d^2=4+4

d^2=2*4

d=√(2*4)

d=2√2 mi  (exact)

d≈2.83 mi  (to nearest hundredth of a mile)
5 0
3 years ago
I need help finding this angle! I will mark you if you help!
Lady_Fox [76]

It's an acute angle because it's smaller than 90 degrees and isn't a straight line.

4 0
3 years ago
Read 2 more answers
What is the smallest integer $n$, greater than $1$, such that $n^{-1}\pmod{130}$ and $n^{-1}\pmod{231}$ are both defined?
olasank [31]

First of all, the modular inverse of n modulo k can only exist if GCD(n, k) = 1.

We have

130 = 2 • 5 • 13

231 = 3 • 7 • 11

so n must be free of 2, 3, 5, 7, 11, and 13, which are the first six primes. It follows that n = 17 must the least integer that satisfies the conditions.

To verify the claim, we try to solve the system of congruences

\begin{cases} 17x \equiv 1 \pmod{130} \\ 17y \equiv 1 \pmod{231} \end{cases}

Use the Euclidean algorithm to express 1 as a linear combination of 130 and 17:

130 = 7 • 17 + 11

17 = 1 • 11 + 6

11 = 1 • 6 + 5

6 = 1 • 5 + 1

⇒   1 = 23 • 17 - 3 • 130

Then

23 • 17 - 3 • 130 ≡ 23 • 17 ≡ 1 (mod 130)

so that x = 23.

Repeat for 231 and 17:

231 = 13 • 17 + 10

17 = 1 • 10 + 7

10 = 1 • 7 + 3

7 = 2 • 3 + 1

⇒   1 = 68 • 17 - 5 • 231

Then

68 • 17 - 5 • 231 ≡ = 68 • 17 ≡ 1 (mod 231)

so that y = 68.

3 0
3 years ago
Find the area of each circle round to the nearest tenth use 20 yard
stiv31 [10]

Answer:

Step-by-step explanation:

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3 years ago
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