we are given that
angle(ACF)=90
angle(ACB)=61
sum of all angles along any line is 180
so, we get
angle(ACF)+angle(ACD)=180
we can plug value
90+angle(ACD)=180
angle(ACD)=90
now, we can use formula
angle(ACD)=angle(ACB)+angle(BCD)
now, we can plug values
and we get
90=61+angle(BCD)
90-61=61-61+angle(BCD)
angle(BCD)=29................Answer
Answer:
1.D
2.c
Step-by-step explanation:
f(m/4)=8(m²/16)-4(m/4)
=m²/2-m
f(-4)=-3(-4)²+5(-4)
=-3(16)-20
=-48-20
=-68
Answer:
23 chalkboards
Step-by-step explanation:
Given:
Mean length = 5 m
Standard deviation = 0.01
Number of units ordered = 1000
Now,
The z factor = 
or
The z factor = 
or
Z = - 2
Now, the Probability P( length < 4.98 )
Also, From z table the p-value = 0.0228
therefore,
P( length < 4.98 ) = 0.0228
Hence, out of 1000 chalkboard ordered (0.0228 × 1000) = 23 chalkboard are likely to have lengths of under 4.98 m.
Answer:
200 divided by 60
Step-by-step explanation:
Answer:
3:4
Step-by-step explanation:
(1/7)/(4/21) = (1/7)×(21/4) = 3/4 = 3:4
