The method of multiplication shown is (a) Ancient Egyptian Method
<h3>Multiplication</h3>
This involves taking the product of at least two factors which could be numbers, expressions or both
From the method shown, we can see that a factor is multiplied by multiples of 2 (i.e. doubling), till it reaches a maximum
This method is associated with the Egyptian.
Hence, the method of multiplication is (a) Ancient Egyptian Method
Read more about multiplications at:
brainly.com/question/10873737
Answer:
Step-by-step explanation:
Since the line segment is only being translated and reflected it would still maintain its length. This is pretty much the only characteristic that would remain the same as te original line segment. It would not maintain the same x-axis positions for both endpoints of the line segment. This is because when it is translated 2 units up it is only moving on the y-axis and not the x-axis. But when it is reflected over the y-axis the endpoints flip and become the opposite values.
Answer: <u>30</u>
Step-by-step explanation:
Yvette- <em>100-7</em>
Isandro- <em>0+3</em>
1.) I'm going to speed up the process and multiply by 5.
Yvette: <em>100-7</em>
7 × 5 = 35
100-35= 65
65-35= 30
Isandro: <em>0+3 </em>
3 × 5 = 15
0+15= 15
15+15=<em> </em>30
2.) If they keep going on this pattern they will have the same number on the 10 round.
Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.
Step-by-step explanation:
Since we have given that
Integers between 10000 and 99999 = 99999-10000+1=90000
n( divisible by 3) = 
n( divisible by 5) = 
n( divisible by 7) = 
n( divisible by 3 and 5) = n(3∩5)=
n( divisible by 5 and 7) = n(5∩7) = 
n( divisible by 3 and 7) = n(3∩7) = 
n( divisible by 3,5 and 7) = n(3∩5∩7) = 
As we know the formula,
n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)
Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.
The domain and range is all real numbers.
<h3>Answer: D) Domain: (-∞, ∞); Range: (-∞, ∞)</h3>
