Answer:
The correct option is the first one.
Step-by-step explanation:
We know that 14 men and 24 women applied for a job. So a total of 38 persons applied for that job.
But there are 4 ways a man can be chosen. It can be the first person chosen, the second, the third of the fourth one.
So we know that the number of ways that four people can be selected out of 38 people is 38C4=73,815.
Also the number of ways 3 woman can be selected is 14*24C3 =14*2024 = 28,336.
Then, the probability of randomly selecting a group with 3 women is 28,336/73,815=0.3838
The correct option is the first one.
Answer:
A. The first 2 are equivalent expressions.
B. The last 2 are equavalent expressions.
De acuerdo con un sistema de ecuaciones, tiene-se que los números son 31 y 84.
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- En el sistema de ecuaciones, tiene-se que los números son x e y.
- Suma de 115, o sea,
- <u>El número mayor es dos veces más 22 unidades que el otro</u>, o sea,
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Primero se encuenta el número menor, <u>reemplazando la segunda ecuación en la primera:</u>
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El número mayor es dado en <u>función de el menor</u>, o sea:
Los números son 31 y 84.
Otro problema resuelto por sistema de ecuaciones es dado en brainly.com/question/24637096
Answer:
the answers are 6.773 and 2.448
Answer:
Yes??
Step-by-step explanation:
Whats the question? Is this your answer? <Confused>
