Question

Please explain your answer as well. THX!!

Answer 1

Answer:

The correct option is the first one.

Step-by-step explanation:

We know that 14 men and 24 women applied for a job. So a total of 38 persons applied for that job.

But there are 4 ways a man can be chosen. It can be the first person chosen, the second, the third of the fourth one.

So we know that the number of ways that four people can be selected out of 38 people is  38C4=73,815.

Also the number of ways 3 woman can be selected is 14*24C3 =14*2024 = 28,336.

Then, the probability of randomly selecting a group with 3 women is 28,336/73,815=0.3838

The correct option is the first one.

Answer 2

Answer:

The correct answer is first option, 0.384

Step-by-step explanation:

It is given that, there are 14 men and 24 women apply for job.

4 are selected random

To find the probability

total people = 14 + 24 = 38

The number people selected in 38C₄ = 38 * 37 * 36 * 35

number of ways 1 men selected in 14C₁ ways

Number of ways 3 women selected is 24C₃ ways

Total number of ways select only 1 men and 3 women = 14C₁ * 24C₃

Required probability = (14C₁ * 24C₃)/(38 * 37 * 36 * 35)

     = 0.3837 ≈ 0.384

The correct answer is first option