Question

Find the equation of a line passing through the point(-3,0) and (2,-3)​

Answer 1

Answer:

y = -3

Step-by-step explanation:

Answer 2

Answer (assuming the question allows it to be written in slope-intercept form):

$y = -\frac{3}{5} x-\frac{9}{5}$

Step-by-step explanation:

1) First, find the slope of the equation. Use the slope formula $m = \frac{y_2-y_1}{x_2-x_1}$, substitute the given points' x and y values, and simplify:

$m = \frac{(-3)-(0)}{(2)-(-3)} \\m =\frac{-3-0}{2+3}\\m = -\frac{3}{5}$

Thus, the slope is $-\frac{3}{5}$.

2) Now, use the point-slope formula $y-y_1 = m (x-x_1)$ and substitute real values for $m$, $x_1$, and $y_1$.

Since $m$ represents the slope, substitute $-\frac{3}{5}$ in its place. Since $x_1$ and $y_1$ represent the x and y values of a point the line crosses, use the x and y values of any one of the given points to substitute into the formula. (Either one is fine. I chose (2,-3).) Then, isolate y to put it into slope-intercept form and find the answer:

$y-(-3) = -\frac{3}{5} (x-(2))\\y + 3 = -\frac{3}{5} x + \frac{6}{5} \\y = -\frac{3}{5} x - \frac{9}{5}$