12. ∆ABD is similar to ∆PQD, so
QD/z = BD/x
Likewise ∆CDB is similar to ∆PQB, so
QB/z = BD/y
Since QD + QB = BD, you have
QD/z + QB/z = BD/x + BD/y
BD/z = BD/x + BD/y
Dividing by BD gives the desired result:
1/x + 1/y = 1/z
13. Triangles ABD, BCD, and ACB are all similar. This means
AB/AC = AD/AB
AB² = AC×AD = (4 cm)×(9 cm)
AB² = 36 cm²
AB = 6 cm
and
BD/CD = AD/BD
BD² = CD×AD = (5 cm)×(4 cm)
BD² = 20 cm²
BD = 2√5 cm
67 & 513,000
I got this because when your putting them together then you sixty seven so 67.
Answer:
D
Step-by-step explanation:
Answer:
C 201 and 770
Step-by-step explanation:
14 and 91 have a common factor of 7 - so not A
B No - as 7 is a factor of 14 and 581
D 12 and 105 are both divisible by 3
So its C
Answer: The measure of central angle XYZ is 3pi/4 radians.
The answer is 96.
