Question

Using the quadratic formula to solve x2 = 5 – X, what are the values of x? -1 + 21 2 -12/19/ 2 5+21 2 1+ 191 2​

Answer 1

Answer:

${x}^{2} = 5 - x \\ { \tt{ {x}^{2} + x - 5 = 0 }} \\ \\ { \bf{x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} }} \\ \\ { \tt{x = \frac{ - 1± \sqrt{21} }{2} }}$