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3 years ago

6) Explain why -4 -2 = -6.

Mathematics

1 answer:

emmasim [6.3K]3 years ago

8 0

Answer:

since both numbers have the same sign the rule of "same sign keep the sign" applies and since they are both negative instead of subtracting you add if they were the inverse of each other you would have to subtract but clearly that isn't needed in this situation.

hope that helps a little!!

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ivanzaharov [21]

Answer:

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4 years ago

The weight of poodles at the dog pound are 22.1 , 24.3, 25.0, 27.1 , .30.0. What is the<br>mode?

Mekhanik [1.2K]

Answer:

None

Step-by-step explanation:

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3 years ago

Let z = ln(x 2 + y), x = ret . and y = ter . Use the Chain Rule to compute ∂z ∂r and ∂z ∂t at the point where (r, t) = (1, 2).\

Natali [406]

By the chain rule,

$\dfrac{\partial z}{\partial u}=\dfrac{\partial z}{\partial x}\dfrac{\partial x}{\partial u}+\dfrac{\partial z}{\partial y}\dfrac{\partial y}{\partial u}$

where $u\in\{r,t\}$ .

We have component partial derivatives

$\dfrac{\partial z}{\partial x}=\dfrac{2x}{x^2+y}=\dfrac{2re^t}{r^2e^{2t}+te^r}$

$\dfrac{\partial z}{\partial y}=\dfrac1{x^2+y}=\dfrac1{r^2e^{2t}+te^r}$

$\dfrac{\partial x}{\partial r}=e^t$

$\dfrac{\partial x}{\partial t}=re^t$

$\dfrac{\partial y}{\partial r}=te^r$

$\dfrac{\partial y}{\partial t}=e^r$

Putting the appropriate pieces together and setting $(r,t)=(1,2)$ , we get

$\dfrac{\partial z}{\partial r}(1,2)=\dfrac{2e^3+2}{e^3+2}$

$\dfrac{\partial z}{\partial t}(1,2)=\dfrac{2e^3+1}{e^3+2}$

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3 years ago

Let g(x) = 3x + 2 If g(x) = 11 find x

Aleks [24]

Answer:

See below:

Step-by-step explanation:

So, for starters, g(x) is just a fancy way of saying that it is a function, it's basically used as $y$ and you can usually use g(x) or y whenever you want unless its a special situation.