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navik [9.2K]
3 years ago
7

A frequently held lottery sells 100 tickets at $1 per ticket every time it is held. one of the tickets must be a winner. a playe

r has $50 to spend. to maximize the probability of winning at least one lottery, should he buy 50 tickets in one lottery or one ticket in 50 lotteries?
Mathematics
1 answer:
n200080 [17]3 years ago
3 0

he should buy 50 tickets in one lottery because that is a 50/100 chance, or 50% chance

buying one ticket in 50 lotteries he would have a 1/100 chance, or 1% chance

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75,15,3 find the 6th term
Karolina [17]

Answer:

0.024

Step-by-step explanation:

75, 15, 3, ...

Now, let's take a look at thus pattern.

You'll notice how the numbers decrease.

Divide 75 by 5.

We get 15

Divide 15 by 5.

We get 3.

Then we have the pattern now.

3 ÷ 5 = 0.6 (4th term)

0.6 ÷ 5 = 0.12 (5th term)

0 12 ÷ 5 = 0.024 (6th term)

I hope it helps.

8 0
3 years ago
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alexandr402 [8]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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Answer:

Step-by-step explanation:

7 0
3 years ago
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NO LINKS OR ELSE YOU'LL BE REPORTED!Only answer if you're very good at Math.
andreev551 [17]

Answer:

D.\ y = 3\sin(2(x + \frac{\pi}{4}))

Step-by-step explanation:

Given

A = 3 --- Amplitude

C = \frac{\pi}{4} --- Right phase shift

Required

Identify the function

A sinusoidal function is defined as:

y = A\sin(B(x + C)) + D

Substitute values for A and C

y = 3\sin(B(x + \frac{\pi}{4})) + D

By comparison, only option (D) has the above format where

y = 3\sin(2(x + \frac{\pi}{4}))

Hence (D) is correct

4 0
3 years ago
Prove that 25^9+5^17is divisible by 30
VLD [36.1K]

Answer:

proof is below

Step-by-step explanation:

Answer:

25^9 + 5^17=

=2^18 + 5^17

=5^17(5+1)

=5^17×6

=5^16×30  is divisible by 30

6 0
2 years ago
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