Right and inequality that expresses the reason the links 5 feet 10 feet and 20 feet could not be used to make a triangle

What is the independent variable of an equation?

bulgar [2K]

The independent variable of an equation is x, or something u can change. in linear equations, for example, it is y=3x+4. and x is the independent variable cause most of the time u will plug in or substitute a number for x.

8 0

3 years ago

What is the x coordinate of the solution? <br> What is the y coordinate of the solution?

Alexus [3.1K]

Answer:

the x coordinate is 1

the y coordinate is 1

Step-by-step explanation:

3 0

2 years ago

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A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. a) E

polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) $\alpha =1-0.98=0.02$

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

$p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }$

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and $z_{\alpha/2}$ is the z-value that let a probability of $\alpha/2$ on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, $\alpha$ by 0.02 and $z_{\alpha/2}$ by 2.33

Where p' and $\alpha$ are calculated as:

$p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02$

So, replacing the values we get:

$0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438$

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence $1-\alpha$ is equal to 98%

It means the the level of significance $\alpha$ is:

$\alpha =1-0.98=0.02$

4 0

2 years ago

To replace a number with another number that tells how many or how much

Papessa [141]

It's subtraction or multiplacation

8 0

2 years ago

The length of a rectangle is 8 centimeters less than its width. What are the dimensions of the rectangle if its area is 240 squa

Dmitriy789 [7]

Answer:
Well, Your best answer will be is 35.
Here's a Explain.
W-5=0
W=5 That's for the width.
L=3*5-8
L=15-8=7 And, That's for the length.
Here's proof.
35=7*5
35=35
Hope That Helps!~

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2 years ago

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