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iren2701 [21]
2 years ago
7

Between 02 30 and 05 15, the same day ,the volume of water in a reservoir increased from 1500 L to 14 700 L. What was the averag

e rate of increased in volume of water, giving your answer in L/h?
Mathematics
2 answers:
marishachu [46]2 years ago
6 0

Answer:

4,800

Step-by-step explanation:

(14,700- 1,500) / 2 h 45 m

= 13,200 / 2.75

= 4,800 L/h

Bond [772]2 years ago
5 0

Time in minutes between 2 30 and 5 15 = 165 minutes= 2.75 hrs

raise in water level = 14700-1500= 13200

the average rate of increased in volume of water, giving your answer in L/h = 13200/2.75 = 4800 L/h

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in a candy store a $5,00 jar of candy is labled 50% off .what is the idscoutn?what si the sales price of the jar of candy?
lisov135 [29]
The discount is $2.50, the new price would be $2.50. Unless you factor in sales tax.
5 0
3 years ago
Four servings of yogurt have 12 grams of protein. What is the number of grams of protein per serving?
tester [92]
If there are 12 grams of protein in all, and 4 servings, in order to get the amount of grams per serving you must divide 12 by 4.

12 divided by 4 = 4.

Therefore, there are 4 grams per serving.
7 0
3 years ago
Read 2 more answers
When electricity (the flow of electrons) is passed through a solution, it causes an oxidation-reduction (redox) reaction to occu
oee [108]

Answer:

a. 135 g

b. 60.6 min

Step-by-step explanation:

a. What mass of Cu(s) is electroplated by running 28.5 A of current through a Cu2+ (aq) solution for 4.00 h? Express your answer to three significant figures and include the appropriate units.

The chemical equation for the reaction is given below

Cu²⁺(aq) + 2e⁻ → Cu(s)

We find the number of moles of Cu that are deposited from

nF = It where n = number of moles of electrons, F = Faraday's constant = 96485 C/mol, I = current = 28.5 A and t = time = 4.00 h = 4.00 × 60 min/h × 60 s/min = ‭14,400‬ s

So, n = It/F = 28.5 A × ‭14,400‬ s/96485 C/mol = ‭410,400‬ C/96485 C/mol = 4.254 mol

Since 2 moles of electrons deposits 1 mol of Cu, then 4.254 mol of electrons deposits 4.254 mol × 1 mol of Cu/2 mol = 2.127 mol of Cu

Now, number of moles of Cu = n' = m/M where m = mass of copper and M = molar mass of Cu = 63.546 g/mol

So, m = n'M

= 2.127 mol × 63.546 g/mol

= 135.15 g

≅ 135 g to 3 significant figures

b. How many minutes will it take to electroplate 37.1 g of gold by running 5.00 A of current through a solution of Au+(aq)?

The chemical equation for the reaction is given below

Au⁺(aq) + e⁻ → Au(s)

We need to find the number of moles of Au in 37.1 g

So, number of moles of Au = n = m/M where m = mass of gold = 37.1 g and M = molar mass of Au = 196.97 g/mol

So, n = m/M = 37.1 g/196.97 g/mol = 0.188 mol

Since 1 mol of Au is deposited  by 1 moles of electrons, then 0.188 mol of Au deposits 0.188 mol of Au × 1 mol of electrons/1 mol of Au = 0.188 mol of electrons

We find the time it takes to deposit 0.188 mol of electrons that are deposited from

nF = It where n = number of moles of electrons, F = Faraday's constant = 96485 C/mol, I = current = 5.00 A and t = time

So, t = nF/It

= 0.188 mol × 96485 C/mol ÷ 5.00 A

= ‭18173.30‬ C/5.00 A

= 3634.66 s

= 3634.66 s × 1min/60 s

= 60.58 min

≅ 60.6 min to 3 significant figures

6 0
3 years ago
Fill in the table for side length and area of different squares.
Gnoma [55]

Answer:

0.09

Step-by-step explanation:

0.03 divided by 100

7 0
3 years ago
TRUE OR FALSE: A translation maps each point to its image along a vector called the translation vector
Tomtit [17]

Answer:

True

Step-by-step explanation:

:) Hope this helps ! x

6 0
2 years ago
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