Answer:
We conclude that the original triangle ΔDEF is dilated by a scale factor of 5/2 to get the image triangle ΔD'E'F'.
Therefore, 'Cárl' is correct. Hence, option 'a' is correct.
Step-by-step explanation:
Checking the location of the vertices of the original triangle ΔDEF
Checking the location of the dilated vertices of the image triangle ΔD'E'F'
- D'(-5, 10)
- E'(5, 10)
- F'(0, 5)
Notice that if we multiply the vertices of the original triangle ΔDEF by 5/2, we get the correct image vertices of image triangleΔD'E'F'
i.e.
D(-2, 4) → D'(5/2 (-2), 5/2 (4)) → D'(-5, 10)
E(2, 4) → E'(5/2 (2), 5/2(4)) → D'(5, 10)
F(0, 2) → E'(5/2 (0), 5/2(2)) → F'(0, 5)
Thus, we conclude that the original triangle ΔDEF is dilated by a scale factor of 5/2 to get the image triangle ΔD'E'F'.
Therefore, 'Cárl' is correct. Hence, option 'a' is correct.
