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Tatiana [17]
3 years ago
8

Perform the operation and get

Mathematics
1 answer:
Alexandra [31]3 years ago
8 0

Answer:

Step-by-step explanation:

(5-2i) ( 5+2i) = (5^2) - ((2i)^2) = 25 - 4i^2

= 25 - 4(-1) = 25 +4 = 29 + 0i

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Please help- will give brainlist. I would appreciate if you told me how you got the answer but you don’t have to
Sever21 [200]

Answer:

66

Step-by-step explanation:

18+15+18+15

3 0
3 years ago
Read 2 more answers
The diameter of the circle above is 86 cm. What is the circumference of the circle? (Use = 3.14.)
Harman [31]
2(3.14)r = Circumference

r = d/2

r = 43

2 x 3.14 x 43 = 270.04 cm
5 0
3 years ago
What are the pattern conbination between these number 18 48 88 128 178 38 68
valentina_108 [34]
18+30=48
48+40=88
88+40=128
128+50=178

Thats all i found so far in the pattern
30,40,40,50
then it drops
by 140 then adds by 30..

I dont know how else to explain it
7 0
3 years ago
Help please as soon as possible
skad [1K]
The value of y will be equal to 4.

Reason : The length of the opposite cord is equal and therefore the distance from the centre to the cord will be equal.

Ans: 3rd option (4)

Hope this helps!
4 0
3 years ago
Read 2 more answers
Squareroot(y-1) + 3 = y
jek_recluse [69]
Note:xy means x times y and x(y) means the same thing

so
first we get rid of square root then
make the equation equal to zero becaues if
xy=0 then x or/and y=0



squareroot(y-1)+3=y

isolate the squareroot
subtrac 3 from boht sides

squareroot(y-1)=y-3

square both sides (since they are equal, you should be able to square both sides and still make it true)

(squareroot(y-1))^2=(y-3)^2
(y-1)=(y-3)(y-3)
y-1=y^2-6y+9
subtrac y from both sides
-1=y^2-7y+9
add 1 to both sides
0=y^2-7y+10
find what two number multiply to make 10 and add to get -7
the answer is -2 and -5

0=(y-5)(y-2)
therfore
y-5=0
and/or
y-2=0

therefor
y=5 or/and 2 might work
let's try out 2
square root(2-1)+3=2
square root(1)+3=2
1+3=2
false
so 2 doesn't work



let's try 5
squareroot(5-1)+3=5
squareroot(4)+3=5
2+3=5
5=5
true

y=5
7 0
3 years ago
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