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3 years ago

Please help will mark brainliest :)

Mathematics

1 answer:

ololo11 [35]3 years ago

8 0

Answer:

Fraction Decimal

4/11 0.36363636 ~ the answer would be "0.36"

Step-by-step explanation:

I hope i helped :)

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Name the property illustrated in this statement. If y - 2 = -8. then y - 2 + 2 = -8 + 2.

Gennadij [26K]

Step-by-step explanation:

first what is 10 take away 2 is 8 then 10 take away 2 is 8 + 2 equals 10 8 + 2 equals 10 so that's how I got the answer 10

4 0

3 years ago

raph the equation with a diameter that has endpoints at (-3, 4) and (5, -2). Label the center and at least four points on the ci

andreyandreev [35.5K]

Answer:

Equation:

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

The point (0,-5), (0,7), (5,0) and (-7,0)also lie on this circle.

Step-by-step explanation:

We want to find the equation of a circle with a diamterhat hs endpoints at (-3, 4) and (5, -2).

The center of this circle is the midpoint of (-3, 4) and (5, -2).

We use the midpoint formula:

$( \frac{x_1+x_2}{2}, \frac{y_1+y_2,}{2} )$

Plug in the points to get:

$( \frac{ - 3+5}{2}, \frac{ - 2+4}{2} )$

$( \frac{ -2}{2}, \frac{ 2}{2} )$

$( - 1, 1)$

We find the radius of the circle using the center (-1,1) and the point (5,-2) on the circle using the distance formula:

$r = \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }$

$r = \sqrt{ {(5 - - 1)}^{2} + {( - 2- - 1)}^{2} }$

$r = \sqrt{ {(6)}^{2} + {( - 1)}^{2} }$

$r = \sqrt{ 36+ 1 } = \sqrt{37}$

The equation of the circle is given by:

$(x-h)^2 + (y-k)^2 = {r}^{2}$

Where (h,k)=(-1,1) and r=√37 is the radius

We plug in the values to get:

$(x- - 1)^2 + (y-1)^2 = {( \sqrt{37}) }^{2}$

$(x + 1)^2 + (y - 1)^2 = 37$

We expand to get:

${x}^{2} + 2x + 1 + {y}^{2} - 2y + 1 = 37$

${x}^{2} + {y}^{2} + 2x - 2y +2 - 37= 0$

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

We want to find at least four points on this circle.

We can choose any point for x and solve for y or vice-versa

When y=0,

${x}^{2} + {0}^{2} + 2x - 2(0) - 35= 0$

${x}^{2} +2x - 35= 0$

$(x - 5)(x + 7) = 0$

$x = 5 \: or \: x = - 7$

The point (5,0) and (-7,0) lies on the circle.

When x=0

${0}^{2} + {y}^{2} + 2(0) - 2y - 35= 0$

${y}^{2} - 2y - 35= 0$

$(y - 7)(y + 5) = 0$

$y = 7 \: or \: y = - 5$

The point (0,-5) and (0,7) lie on this circle.

3 0

3 years ago

Convert 26\%26%26, percent to a fraction in simplest form.

Korolek [52]

26 percent?

A percent is a fraction out of a hundred. 5% is 5 out of one hundred, 20% is 20 out of one hundred, etc.

So 26/100 simplified is 13/50.

6 0

3 years ago

Simplify the expression 6x+12y+5+2y+8 what is the coefficient of y and what is the constant

frez [133]

We want to find the coeficient of the y terms when added together so find all the y terms

+12y and +2y
we add them together
12y+2y=(12+2)y=(14)y=14y
coeficient is 14

the constant is the number that is set already or the number that doesn't have it multiplied by a placeholder exg. 4 is a constnat but 4x is not so find the constants
+5 and +8
we add
5+8=13
the constant is 13

y coeficient=14
constant=14

5 0

3 years ago

Read 2 more answers

2(v–11) please help me solve this

nika2105 [10]

Answer: 2v-22

Step-by-step explanation:

2(v)=2v

2(-11)= -22

2v - 22

6 0

3 years ago