Answer:
When i took it i chose C and was right. I'm not sure if we use the same school but it was my answer. Hope it helps.
Step-by-step explanation:
For fog or f(g(x)), plug g(x) into f(x):
2(3x+2)²+x
Then simplify:
2( (3x+2)(3x+2) )+x
2( 9x²+12x+4 )+x
18x²+24x+8 +x
18x²+25x+8
Then you can simplify this further using factoring methods to:
(2x+1)(9x+8)
Hope this helps!! :)
Answer:
D
Step-by-step explanation:
I'm big brain. hbvuivyvjbbu
Alrighty
squaer base so length=width, nice
v=lwh
but in this case, l=w, so replace l with w
V=w²h
and volume is 32000
32000=w²h
the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW
alrighty
we gots
SA=W²+4HW and
32000=W²H
we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute
SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W
take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?
0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W
so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H
the box is 20cm height and the width and length are 40cm
