Can anyone tell me how to do this? (Steps) and can you answer these two questions for me plz
1 answer:
Ax²+bx+c=0
The formula to solve for x is:
So for 3x²+13x+10=0, plug in the data
x=-13±√13²-4(3)(10) / 2(3)
x=-13±√169-120 / 6
x=-13±√49 /6
x=-13<span>±7 / 6
x=-13+7/6
x=-6/6
x=-1
x=-13-7/ 6
x=-20/6 or 3.3repeating
3x</span>²+14x+15=0
x=-14±√14²-4(3)(15) / 2(3)
x=-14±√196-180 /6
x=-14<span>±</span>√16 / 6
x=-14+4/6
x=-10/6 or 1.6repeating
x=-14-4/6
x=-18/6
x=-3
The formula to solve for x is:
So for 3x²+13x+10=0, plug in the data
x=-13±√13²-4(3)(10) / 2(3)
x=-13±√169-120 / 6
x=-13±√49 /6
x=-13<span>±7 / 6
x=-13+7/6
x=-6/6
x=-1
x=-13-7/ 6
x=-20/6 or 3.3repeating
3x</span>²+14x+15=0
x=-14±√14²-4(3)(15) / 2(3)
x=-14±√196-180 /6
x=-14<span>±</span>√16 / 6
x=-14+4/6
x=-10/6 or 1.6repeating
x=-14-4/6
x=-18/6
x=-3
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Answer:
(a) The sum of the previous term and 9
(b) 36, 45, 54
Step-by-step explanation:
Given
Sequence: Arithmetic Progression
Solving (a): Describe the relationship in each term
First, we calculate the common difference (d)
In arithmetic progression:
Take n as 2
Where
<em>The relationship is: The sum of the previous term and 9</em>
Solving (b): The next three terms
As said in (a) each term is derived from a sum of 9 and the previous term
So, we have:
Hence, the next three terms are: 36, 45 and 54