Can anyone tell me how to do this? (Steps) and can you answer these two questions for me plz
1 answer:
Ax²+bx+c=0
The formula to solve for x is:
So for 3x²+13x+10=0, plug in the data
x=-13±√13²-4(3)(10) / 2(3)
x=-13±√169-120 / 6
x=-13±√49 /6
x=-13<span>±7 / 6
x=-13+7/6
x=-6/6
x=-1
x=-13-7/ 6
x=-20/6 or 3.3repeating
3x</span>²+14x+15=0
x=-14±√14²-4(3)(15) / 2(3)
x=-14±√196-180 /6
x=-14<span>±</span>√16 / 6
x=-14+4/6
x=-10/6 or 1.6repeating
x=-14-4/6
x=-18/6
x=-3
The formula to solve for x is:
So for 3x²+13x+10=0, plug in the data
x=-13±√13²-4(3)(10) / 2(3)
x=-13±√169-120 / 6
x=-13±√49 /6
x=-13<span>±7 / 6
x=-13+7/6
x=-6/6
x=-1
x=-13-7/ 6
x=-20/6 or 3.3repeating
3x</span>²+14x+15=0
x=-14±√14²-4(3)(15) / 2(3)
x=-14±√196-180 /6
x=-14<span>±</span>√16 / 6
x=-14+4/6
x=-10/6 or 1.6repeating
x=-14-4/6
x=-18/6
x=-3
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The answer is A because when you add the angles to get they equal 180. Then just solve for x.
The drawing isn't to scale
The drawing isn't to scale
Answer:
Step-by-step explanation:
Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P and verify if it is the closest to A or there is another one of the line
Having the point P(3,5) substitue x to verify y
y=2*(3)-1=6-1=5 (3,5)
Now if the angle formed by A and P is 90º it means that it is the closest point, otherwise that point must be found
and we found the distance PQ and QA
; ,
be the APQ triangle we must find <APQ through the cosine law (graph 2).
