Answer:The solution is in the attached file
Step-by-step explanation:
Step-by-step explanation:
(1\2)^4 x 1\16 x 1\8 x 1\4 [1/2^4=16]
1/16 x 1/512
=>1/2048
First write it in vertex form :-
y= a(x - 2)^2 + 3 where a is some constant.
We can find the value of a by substituting the point (0.0) into the equation:-
0 = a((-2)^2 + 3
4a = -3
a = -3/4
so our equation becomes y = (-3/4)(x - 2)^2 + 3
1. x greater than or equal to 4 (B)
2. x does not equal 4 (C)
3. A
4. B
5. B
6. A
7. B
8. C
(The pictures were out of order but i did it by number shown in the pictures. Hope this helps.)
Answer:
c. [1.771;4.245] feet
Step-by-step explanation:
Hello!
The variable of interest is
X: height of a student at UH
X~N(μ;σ²)
You have to estimate the population standard deviation using a 95% confidence interval.
The statistic to use for the interval is a student Chi-Square with n-1 degrees of freedom. First you have to calculate the CI for the population variance:
![[\frac{(n-1)S^2}{X^2_{n-1;1-\alpha /2}} ;\frac{(n-1)S^2}{X^2_{n-1;\alpha /2}} ]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%28n-1%29S%5E2%7D%7BX%5E2_%7Bn-1%3B1-%5Calpha%20%2F2%7D%7D%20%3B%5Cfrac%7B%28n-1%29S%5E2%7D%7BX%5E2_%7Bn-1%3B%5Calpha%20%2F2%7D%7D%20%5D)


n=12
S= 2.5
![[\frac{11*6.25}{21.920} ;\frac{11*6.25}{3.816}} ]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B11%2A6.25%7D%7B21.920%7D%20%3B%5Cfrac%7B11%2A6.25%7D%7B3.816%7D%7D%20%5D)
[3.136; 18.016] feet²
Then you calculate the square root of both limits to get the CI for the population standard deviation:
[√3.136; √18.016]
[1.771;4.245] feet
I hope this helps!